解方程组(x-1)(2y+1)=2(x+1)(y-1) x(2+y)-6=y(x-4)答案是?..急用!

要求 解方程组：｛(X-1)(Y+1)=(X+1)(Y+1)｛X(2+Y)-6=Y(X-4) 解方程组：2(x-y)/3-x+y/4=-1 ,6(x+y)-4(2x-y)=16 解二元一次方程组{3(x+y)-4(x-y)=4,x+y/2+x-y/6=1 解方程组3(x+y)-4(x-y)=4和(x+y)/2+(x-y)/6=1 解二元一次方程组{3(x+y)-(x-y)=4,x+y/2+x-y/6=1 解二元一次方程组：3(x+y)-4(x-y)=4,x+y/2+x-y/6+1 解方程组｛ 3x-4y(x-y)=3 { 2x-3y=1 2(x+y)-3(x-y)=1 6(x+y)+7(x-y)=51 解方程组 解方程组﹛2(x+y)-3(x-y)=1 6(x+y)+7(x-y)=51 一道二元一次方程组!3(x+y)-4(x-y)=4,(x+y)/2+(x-y)/6=1 已知方程组4x+2y=1,20x+8y,求x,y 1/2x-2y=-74,x-6y=-12解方程组,x／5-y／2=2,2x+3y=4解方程组