用复变函数证明arctan (1/2) + arctan (1/3) =π/4
求证:arctan 1/2+arctan 1/5+arctan 1/8=π/4
arctan(-2)+arctan(-3)=?
证明:arctan(n+1)-arctan(n)=arctan{1/[1+n(n+1)]}
arctan(1/3)+arctan(1/2)的值为?
求值:sin[1/2arctan(-4/3)]
函数y=arctan(1+x^2)求dy/dx
y=arctan(x^2+1)
(arctan√3) - (arctan-1)求解
arctan(-1)=-π/4,怎么算的?
证明|arctan(x+1)-arctanx|≤1
arctan(n+1)-arctan(n) 如何计算 答案是+π/4
求函数y=π+arctan x/2 的反函数