怎么算啊这个:X²+4X+Y²-2Y+5=0 则X²+Y²=?
已知(x²+y²)(x²+y²-6)+9=0 ,求x²+y²
x²-2x+y²+4y+5=0,求x²+2y的值
|x+2y+3|+(2x+y)²=0求x²-xy+y²
已知x²+y²-4x+6y+13=0,求x²+2y/x²-3y²的值
方程组{x²+y²=10(1)x²-3xy+2y²=0(2)怎么解
已知X²-5XY+6Y²=0,求(X²+3XY)\2Y²的值
2x-y=2,求[(x²+y²)-(x-y)²+2y(x-y)]÷4y
已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y
x²+y²+4x-8y+20=0,求分式x²-y²/xy的值
已知:x²+y²+4x+6y+13=0 求:x²+y²的值
x²+y²+4x-8y+20=0,求(x²-y²)÷xy的解
1.已知x²-10x+y²+4y+29=0,求x²+y²值.