max=1000(x11+x12+x13)+700(x21+x22+x23)+600*(x31+x32+x33);

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max=1000*(x11+x12+x13)+700*(x21+x22+x23)+600*(x31+x32+x33);
(8*x11+6*x21+5*x31)=2/3(1-0.15)*(8*x12+6*x22+5*x32);
(8*x13+6*x23+5*x33)=1/2(1-0.15)*(8*x12+6*x22+5*x32);
(8*x11+6*x21+5*x31)=4/3(1-0.10)*(8*x13+6*x23+5*x33);
8*x11+6*x21+5*x31

max=1000*(x11+x12+x13)+700*(x21+x22+x23)+600*(x31+x32+x33);
(8*x11+6*x21+5*x31)=2/3*(1-0.15)*(8*x12+6*x22+5*x32);
(8*x13+6*x23+5*x33)=1/2*(1-0.15)*(8*x12+6*x22+5*x32);
(8*x11+6*x21+5*x31)=4/3*(1-0.10)*(8*x13+6*x23+5*x33);
8*x11+6*x21+5*x31

model: min=800*x11+1000*x12+1200*x13+700*x21+500*x22+700*x23 lingo 提示语法错误 Max=12*x31+7*x32+13*x33-0.5*x21-0.5*x22-0.5*x23 求问lingo大神!model:max=3*x11+9*x12-7*x21-x22-x31+5*x32-6*x41;0. LINDO程序max 3100x11+3100x12+3100x13+3800x21+3800x22+3800x23+3 min=2*x11+x12+3*x13+x14+2*x15+4*x21+2*x22+x23+3*x24+x25+2*x3 怎么用lingo实现编写这一步?(x11+x12+x13)*0.5+(x21+x22+x23)*0.3 用lingo软件解题min s=50*X11+60*X12+70*X13+60*X21+110*X22+160*X23S min @abs(x21+x31-2/3)+@abs(x22+x32+x42-5/3)+@abs(x33+x43-2/3 lingo 整数我设定的变量是X11,X12,X13,X17X21,X22,X23,X27,X231,X232,X233 请问怎么用范德蒙德行列式解下列行列式 1 1 1 1 x1 x2 x3 y x12 x22 x32 y2 x13 x23 matlab循环计算x11=0.3 x21=0.4x12=0.254273-0.155503x11+0.560625x2 已知一组正数x1,x2,x3,x4,x5,的方差为：S2=(x12+x22+x32+x42+x52-20)