∫1/2e^(-y)dy怎么算
∫(1/(y-y^2))dy 等于多少?怎么算?
∫e^(-2x)dx∫e^(-y)dy
1,y=e^tanxcos^3x,求dy 2,函数y=y(x)由方程e^(x+y)+arctan(xy)=0确定,求dy
定积分详解 ∫ (1,0)(y(e^y)-y) dy
∫( e^x sin y- y )dx + (e^x cos y - 1)dy,是(2,0)的半圆周y=√2x-x^2
∫(0,1)dx∫(0,x)e^(-y)dy怎么解?
∫(2,0) (x+y)dx+(x–y)dy怎么算 (1,0)
∫1/(y^2-1)*dy怎么求积分
设y^2=1+x*(e^y) 求dy
1+(dy/dx)^2=y^2怎么解
dy/dx,y=(1+x+x^2)e^x
求dy/dx y=e^(2x+1)