若lim(x-0)[(x^2/x+1)-ax-b]=0,求常数a,b
已知lim x→0(((根号下1+x+x^2) - (1+ax))/x^2)=b,求常数a、b的值
已知lim{(x^2+1)/(x^3+x)-ax-b}=0(x趋近无穷),求a,b的值
设lim((x^2+1)/(x+1) -ax-b)=0,求a,b. x趋向无穷大
设lim((x^2+1)/(x+1) -ax-b)=0,求a,b.x趋向无穷大
若lim x→ -∞时,(根号下4x^2-x+4)+ax =b .求常数a和b分别是几?
已知lim(x→2)(x^2+ax+b)/(x^2-x-2)=2则常数a,b的取值分别是 求详解.
高数极限问题.求常数a b使 lim 三次根号下(1-x^6)-ax^2-b成立.
lim趋向正无穷(根号下X^2+X-1 -AX)=b ,求a ,b
1.若lim x趋向无穷 ((4x^2+1)/(x+1)-ax+b)=0,求a,b的值
已知limx→∞[(x^2+1)/(x+1)-(ax+b)]=0,求常数a,b的值
已知lim(x→2)(x^2+ax+b)/(x-2)=3则常数a,b的取值分别是 求详解.
试确定常数a,b,使lim{(3次根号下√(1-x^3 ))-ax-b)=0(x趋于0″ )