定积分∫(x^2+a^2) ^ 1/2dx积分上限—a积分下限0
来源:学生作业帮 编辑:神马作文网作业帮 分类:数学作业 时间:2024/11/17 05:07:51
定积分∫(x^2+a^2) ^ 1/2dx积分上限—a积分下限0
∫[0,a]√(x²+a²) dx,令x=a*tany => dx=a*sec²y dy
当x=0,y=0 // 当x=a,y=π/4
原式= ∫[0,π/4]√(a²*tan²y+a²) * a*sec²y dy
= ∫[0,π/4]√[a²(1+tan²y)] * a*sec²y dy
= ∫[0,π/4]a*secy*a*sec²y dy
= a²∫[0,π/4]sec³y dy
= a² * [(1/2)secy*tany + (1/2)ln|secy+tany|] [0,π/4]
= a² * [(1/2)sec(π/4)tan(π/4) + (1/2)ln(sec(π/4)+tan(π/4))] - a² * [(1/2)ln(1)]
= a² * [(1/2)(√2)(1) + (1/2)ln(√2+1)]
= a²/√2 + (a²/2)ln(√2+1)
有关∫sec³x dx的积分:
J = ∫sec³x dx = ∫secx dtanx
= secx*tanx - ∫tanx dsecx
= secx*tanx - ∫tanx*secxtanx dx
= secx*tanx - ∫(sec²x-1)*secx dx
= secx*tanx - J + ∫secx dx
2J = secx*tanx + ∫secx(secx+tanx)/(secx+tanx) dx
J = (1/2)secx*tanx + (1/2)∫(secxtanx+sec²x)/(secx+tanx) dx
J = (1/2)secx*tanx + (1/2)∫d(secx+tanx)/(secx+tanx) dx
J = (1/2)secx*tanx + (1/2)ln|secx+tanx| + C
当x=0,y=0 // 当x=a,y=π/4
原式= ∫[0,π/4]√(a²*tan²y+a²) * a*sec²y dy
= ∫[0,π/4]√[a²(1+tan²y)] * a*sec²y dy
= ∫[0,π/4]a*secy*a*sec²y dy
= a²∫[0,π/4]sec³y dy
= a² * [(1/2)secy*tany + (1/2)ln|secy+tany|] [0,π/4]
= a² * [(1/2)sec(π/4)tan(π/4) + (1/2)ln(sec(π/4)+tan(π/4))] - a² * [(1/2)ln(1)]
= a² * [(1/2)(√2)(1) + (1/2)ln(√2+1)]
= a²/√2 + (a²/2)ln(√2+1)
有关∫sec³x dx的积分:
J = ∫sec³x dx = ∫secx dtanx
= secx*tanx - ∫tanx dsecx
= secx*tanx - ∫tanx*secxtanx dx
= secx*tanx - ∫(sec²x-1)*secx dx
= secx*tanx - J + ∫secx dx
2J = secx*tanx + ∫secx(secx+tanx)/(secx+tanx) dx
J = (1/2)secx*tanx + (1/2)∫(secxtanx+sec²x)/(secx+tanx) dx
J = (1/2)secx*tanx + (1/2)∫d(secx+tanx)/(secx+tanx) dx
J = (1/2)secx*tanx + (1/2)ln|secx+tanx| + C
计算定积分 ∫( √x^2)dx(a>0)(上限a ,下限-a)
求定积分∫x^2[根号(a^2-x^2)]dx,上限a,下限0
求定积分∫|x|dx,上限1,下限-2
∫√(1-x^2)dx 积分上限1 下限0 求定积分
求定积分∫(dx)/(x+(1-x^2)^1/2),积分上限是1,积分下限是0,
积分上限1,积分下限-1,dx/(1+x^2)^2的定积分解答过程
∫x/(1+x^2)^3 dx的定积分 其中上限a=1 下限b=0
求定积分∫sin(x^2)dx,积分上限2,下限-1
定积分∫|lnx|dx 上限2下限1/2
求定积分:arcsinx dx上限1/2,下限0
求定积分 上限1 下限0 ∫ (x^4 dx)/ [(2-x^2)^3/2]
定积分 上限为1 下限为0 ∫ (x^2)/(1+x^2)^3 dx