3x-y+z=4 ① 2x+3y-2z=12 ② 3x+2y=66 ③
①x+y+z=6 3x-y+2z=12 x-y-3z=-4 ②x+y-z=2 4x-2y+3y+8=0 x+3y-2z-
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
解三元一次方程组 2x=3y① 4y=5z② x+y+z=66③ 第二道 3x-y+z=4① 2x+3y-z=12② x
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
已知x/2=y/4=z/7,求①x:y:z.②若2x+y+3z=58,分别求x,y,z的值.③求x+y/x+z的值.
如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y,
x/2=y/3=z/5 x+3y-z/x-3y+z
1.x+y=16,y+z=12,z+x=102.3x-y+z=4,2x+3y-z=12,x+y+z=63.x+y+z=6
x+y+z=2 ① 2x+3y+z=38 ① x+y=3 3x-y-4z=5 ② 3x+4y+2z+56 ② y+z=5
2x+3y+z=38 ① 3x+4y+2z=56 ② 4x+5y+z=66 ③
解方程组{3x+y-z=4,2x-y+3z=12,x+y+z=6}
解方程{3x -y+z=4 2x+3y-z=12 x+y+z=6