the line y=3x+k is tangent to the curve x^2+xy+16=0 find pos
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the line y=3x+k is tangent to the curve x^2+xy+16=0 find possible values of k
直线 y=3x+k与曲线x^2+xy+16=0相切, 求 k 的可能值.
is tangent to : 与.相切
再问: 没有问你是什么意思,问你怎么做。。。。。。不过还是谢谢
再答: x^2 + x(3x+k) + 16 = x^2 + 3x^2 + kx + 16 = 0 4x^2 + kx + 16 = 0 (2x + 4 )^2 = 4x^2 +16x + 16 = 0 k = 16 ; k 的可能值
is tangent to : 与.相切
再问: 没有问你是什么意思,问你怎么做。。。。。。不过还是谢谢
再答: x^2 + x(3x+k) + 16 = x^2 + 3x^2 + kx + 16 = 0 4x^2 + kx + 16 = 0 (2x + 4 )^2 = 4x^2 +16x + 16 = 0 k = 16 ; k 的可能值
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