解不等式:(1-3y)2+(2y-1)2>13(y-1)(y+1)

y/3≤y+1解不等式 解方程：3y^2-(2y+1)(y-1)=(y-5)(y+1) 解方程3y^2-(2y+1)(y-2)=(y-5)(y-1) 已知y满足不等式(-y+1/2)-y＞2+（y+2/3）,化简/y+1/+/2y-1/=_____ 急! 计算不等式题(1+3分之y)(y的平方+1)>(1-2分之y-2)(y的平方+1) 解方程(1-3y)^2+(2y-1)^2=13(y-1)(y+1) 解方程y-[3y-1]等于5【y+2] 画出不等式组 x-2y+1 [(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y 已知y满足不等式2分之y+1-y>2+三分之y+2,化简y加一的绝对值+2y-1的绝对值 整数x.y满足不等式x^+y^+1小于等于2x+2y.则x+y的值有 解3y+5/3y-6=1/2+5y-4/2y-4