x+2y+3z=14 2x+y+z=7 3x+y+2z=11 求XYZ

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x+2y+3z=14 (1)
2x+y+z=7 (2)
3x+y+2z=11 (3)
(2)-(1)
x-(y+2z)=-7 (4)
(3)+(4)
4x=4
x=1,分别代入(2)、(3),整理,得
y+z=5 (5)
y+2z=8 (6)
(6)-(5)
z=3,代入(5)
y=5-z=5-3=2
x=1 y=2 z=3
xyz=1×2×3=6

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