化简f(x)=(1+cos2x)sin^2x

已知f(sin-1)=cos2x+2,求f(x) f(x)=((1+cos2x)^2-2cos2x-1)/(sin(π/4+x)sin(π/4-x)) f(x)=(1+cos2x)/[4sin(pai/2+x)]-asin(x/2)cos(pai-x/ 已知函数f(x)=2cos2x+sin²x 已知函数f(x)=(1+cos2x)sin^2(x),x属于R,则f(x)周期?奇偶? 已知函数f(x）=（1+cos2x)sin∧2x,x∈R,则f(x)是 已知函数f(x)=(1+cos2x)sin^2x,x属于R,则f(x)是 已知函数f(x)=（4cos^4x-2cos2x-1）/[sin(π/4+x)·sin^2(π/4-x)]化简 已知函数f(x)=（4cos^4x-2cos2x-1）/[sin(π/4+x)·sin(π/4-x)]化简 f(x)=sin(2x-5/6π)+2cos2x化简 f(x)=2cos2x+sin^2x,化简.详细步骤! 化简f(x)=2cos2x+sin^2x-4cosx