(1)x²+7x+10 (2)x²-2x-8 (3)y²-7y+12 (4)x²
(2x+y)²-y(y+4x)-8x等于?
已知x-y=1,y≠0,求{(x+2y)²+(2x+y)(x+4y)-3(x+y)(x-y)}÷y的值.
计算:(1)2/(x+y)+4y/x²-y²(2)x²/x+y-x+y
x(x-y)-y(y-x)+(x-y)²因式分解
因式分解x²(x-2y)+y²(2y-x)
x²+7x+10 x²-2x-8 y²-7y+12 x²+7x-18
12x²-3y² (2x+y)²-(x+2y)²
已知一个多项式加﹣2x³+4x²y+5y³得到X³-3X²Y+2Y
分解因式 8(x²-2y²)-x(7x+y)+xy
2(x+y)+(﹣5x+2y) 合并同类项 3X²-[8X﹣(5X﹣2)﹣7X²]
计算:[(x+¼y)+(x-¼y)](2x²-1/8y²)
1、已知实数x、x满足x²+y²-xy+2x-y+1=0,试求x、y的值.