自变量x,y满足 x-2y+1=0 x
已知x,y满足约束条件:x-y+1>=0,x+y-2>=0,x
变量x,y满足x-2y=0,x
已知一次函数Y=-2X+12满足条件Y>0,2X>Y,则自变量X的取值范围是_________
设Z=X+Y,其中X,Y满足X+2Y>=0,X-Y
当自变量x的取值满足什么条件时,函数y=5x+17的值满足下列条件?(1)y=0 (2)y=—7(3)y=20
当自变量x取值满足什么条件时、函数y=5x+17的值满足下列条件、(1)y=0(2)y=-7(3)y=20、求解
当自变量x的取值满足什么条件时,函数y=5x-17的值满足下列条件?(1)y=0(2)y=-7(3)y=20
若x,y满足|2x-y-3|+|3x+2y+1|=0,则x= y=
已知实数x,y满足x²+y²-xy+2x-y+1=0 求x y
y=√x+2/[(√2x-1)-x],求自变量x的范围
当自变量x的取值满足什么条件时,函数y=3x+8的值满足y=-7,y>0 y
x>1,y>0,且满足xy=x^y,x/y=x^3y,求x+y