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分式运算:(1)x^2-5x+6分之x^2-6x+8 · x^2-3x-4分之x^2-2x-3 (2)(a-b分之a+b

来源:学生作业帮 编辑:神马作文网作业帮 分类:数学作业 时间:2024/11/14 01:15:33
分式运算:(1)x^2-5x+6分之x^2-6x+8 · x^2-3x-4分之x^2-2x-3 (2)(a-b分之a+b-a分之b)· a-b分之ab
(3)1÷(x- x^3分之2x^2-1)-x分之x-1 ÷(x-x分之1)
(4)a^2+a-6分之a^2+5a+4 ÷a^2-6a+8分之a^2+3a-4 -1
(急速)
分式运算:(1)x^2-5x+6分之x^2-6x+8 · x^2-3x-4分之x^2-2x-3 (2)(a-b分之a+b
(1)x^2-5x+6分之x^2-6x+8 · x^2-3x-4分之x^2-2x-3
=(x-2)(x-4)/(x-2)(x-3)*(x-3)(x+1)/(x-4)(x+1)
=1
(2)(a-b分之a+b-a分之b)· a-b分之ab
=[a/(a-b)-b/(a-b)*ab/(a-b)
=ab/(a-b)
(3)1÷(x- x^3分之2x^2-1)-x分之x-1 ÷(x-x分之1)
=1÷[(1-2x²)/x(x²-1)]-(x-1)/x÷(x²-1)/x
=x(x²-1)/(1-2x²)-1/(x+1)
这个题目不清楚
(4)a^2+a-6分之a^2+5a+4 ÷a^2-6a+8分之a^2+3a-4 -1
=(a+1)(a+4)/(a+3)(a-2)÷(a+4)(a-1)/(a-2)(a-4)-1
=(a+1)(a-4)/(a+3)(a-1)-1
=(a²-3a-4-a²-2a+3)/(a+3)(a-1)
=(1-7a)/(a+3)(a-1)