ln(x²+y²)½=arctany/x 求dy/dx

设y=2arctany/x,求dy/dx,dy^2/d^2x. 设函数y=y(x)由方程ln(x^2+y^2)^1/2=arctany/x所确定,求dy/dx. ln[根号（x^2+y^2）] =arctany/x 求dy x=y+arctany 求隐函数的导数dy/dx. 求(1+y^2)dx=(arctany-x)dy的通解. 设 x/y=ln(y/x) ,求 dy/dx 求微分方程 x*dy/dx=y*ln(y/x) . y/x=ln(xy) 求详 dy/dx y/x=ln(xy) 求dy/dx ln y = e^x sinx 求dy/dx. y=ln√1-2x,求dy/dx! 1 求方程（1+y^2）dx=(arctany - x)dy的通解 2求方程（x-2xy- y^2）y’+ =0的通解