(9x³-6x²-5x+2)÷(3x-1)=?
(1) x-3/x-2 - x-5/x-4=x-7/x-6 - x-9/x-8
(x³-1)÷(x-1)=?(9x³-6x²-5x+2)÷(3x-1)=?计算
解方程(x-2)X(x的平方-6x-9)=x(x-5)X(x-3)
已知x²+3x-1=0 求(x-3)÷(3x²-6x)÷(x+2-[5÷(x-2)])的值
已知x²+3x-1=0,求(x-3)/(3x²-6x)÷(x+2-5/(x+2))的值
已知(x+1)(x²+2x+3)=x³+3x+5x+3,那么,将x³+3x²+5
9x+6x²-3(x-2/3x²),其中x=-2 1/4(-4x²+2x-8)-(1/2x
解方程①(x+3/x-1)²-5(x+3/x-1)+6=0 ②x²-2/x+3-6x+18/x
|X-1|+|X-2|+|X-3|+|X-4|+|X-5|+|X-6|+|X-7|+|X-8|+|X-9|+|X-10|
y=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10)的导数在x=1
设函数f(x)=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10),
计算(x*x+4x+5)/(x+2)-(x*x+6x+10)/(x+3)+1