x²+y²=16-[x²+(y-2)²] 化简是得 x²+y²
(2x-y)²-4(x-y)(x+2y)
化简:(2x-y)²-4(x-y)(x+y)
因式分解:x²(x-y)+(y-x)
已知x/y=2,求2x(x+y)-y(x+y)/4x²-4xy+y²
2.(x+y)²(x-y)²-(x-y)(x+y)(x²+y²)
已知x²+y²+5=2x+4y,求【2x²-(x-y)(x-y)】【(x+y-1)(x-y
求因式分解(x-y)²-2(x-y)³和(x+y)(x-y)-x(x-y)
[(y-2x)(-2x-y)-4(x-2y)²]*2y,其中x=1,y=2
x²-x²y+xy²-x+y-y²,让我看得懂
(x-2y)²+(2x-4y)(x+y)+(x+y)²
若|x+2y-1|+y²+4y+4=0,求(2x-y)²-2(2x-y)(x+2y)+(x+2y)&
(x-y)³+9(x-y)-6(x-y)²