若log(2a)((1+a^2)/(1+a))
若log(a)(a^2+1)
log(2)(a)>log(1/2)(-a) 解不等式
log a(1/2次方) x等于2log a
27-1/ 若a>0,b>0,a*b>1,log(1/2)[a]=ln2,则log(a)[b]与log(1/2)[a]的
已知a>2,求证log(a-1)>loga(a+1)
若a>0且a≠1,且log a(2a+1)<log a 3a<0,求a的取值范围
[log (底数为a) x]=[1\2log (底数为a) b ] - [ log (底数为a)c]求X
证明对数运算法则(1)log(a)(MN)=log(a)(M)+log(a)(N); (2)log(a)(M/N)=
log a(2/3)
log(a)2
若a²>b>a>1,试比较log b b/a ,log b a,log a b的大小
(1)利用关系式log(a)N=ba^b=N证明换底公式 log(a)N=log(m)N/log(m)a (2)利用(1