-2x³y+4x²y-2xy

2x+y=0,求4x²+2xy(x+y)+y³ 多项式因式分解 1,(x-y)³-(x-y)²(x+y) 2,x(x²-xy)-(4x&# x³y-2x²y²+xy³ (-x-2y)(x²-2xy+4y²) 【分解因式】 x²-xy+4分之1y² x²y-2xy²+y³ a（x 化简(x²y-4y²)/(x²+4xy+4y²)*[(4xy)/(x-2y)+x 计算x²y³-2x(4xy³) 已知x/y=2,求2x(x+y)-y(x+y)/4x²-4xy+y² (5.2x²y-3.4xy+8x³)+2(2.2xy-4x³-2.3x²y)其中 x^2y+4xy+4y 先化简,再求值:{xy(x²-3y)+3xy²}(-2xy)+x³y²(2x-y 3x²y+xy²-[2xy²-4x²y+（x²y-2xy²）