3x-y+2z=-1 4x+y+z=5 x-2y-z=-2
x/2=y/3=z/5 x+3y-z/x-3y+z
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
{x+y+z=1;x+3y+7z=-1;z+5y+8z=-2
x-y-z=-1 3x+5y+7z=11 4x-y+2z=-1 分别求出x=?y=?z=?
已知x::y:z=3:4:5,(1)求x+y分之z的值;(2)若x+y+z=6,求x,y,z.
{5x-3y+z=2{5x+2y-4z=3{-5x+y-z=2 {x-y-z=-1{3x+5y+7z{4x-y+2x=-
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
已知x:y:z=4:5:7,求:(1)2x+3y+z/5z; (2)x+y/y+z.
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai
x+y+z=2 4x+2y+z=4 2x+3y+z=1
x+y+z=2 x-3y+2z=1 2x+2y+z+5 要具体步骤..
3x+2y+z=14 ,x+y+z=10,z+2x+3y=1 5