已知log14 7=a,log14 5=b,用a,b表示log35 28
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已知log14 7=a,log14 5=b,用a,b表示log35 28
log 14 7 = lg 7 / lg 14
log 14 5 = lg 5 / lg 14
A = lg 7 / lg 14 = lg 7 / (lg 7 + lg 2)
B = lg 5 / lg 14 = (1 - lg2) / (lg 7 + lg 2)
通过以上两式可得:
lg 7 = A / (1 - A + B)
lg 2 = (1 - A) / (1 - A + B)
log 35 28
= lg 28 / lg 35
= (lg 7 + 2lg 2) / (lg 7 + lg 5)
= (lg 7 + 2lg 2) / (lg 7 + 1 - lg2)
= [A / (1 - A + B) + 2(1 - A) / (1 - A + B)] / [A / (1 - A + B) + 1 - (1 - A) / (1 - A + B)]
= [(2 - A) / (1 - A + B)] / [(A + B) / (1 - A + B)]
= (2 - A) / (A + B)
log 14 5 = lg 5 / lg 14
A = lg 7 / lg 14 = lg 7 / (lg 7 + lg 2)
B = lg 5 / lg 14 = (1 - lg2) / (lg 7 + lg 2)
通过以上两式可得:
lg 7 = A / (1 - A + B)
lg 2 = (1 - A) / (1 - A + B)
log 35 28
= lg 28 / lg 35
= (lg 7 + 2lg 2) / (lg 7 + lg 5)
= (lg 7 + 2lg 2) / (lg 7 + 1 - lg2)
= [A / (1 - A + B) + 2(1 - A) / (1 - A + B)] / [A / (1 - A + B) + 1 - (1 - A) / (1 - A + B)]
= [(2 - A) / (1 - A + B)] / [(A + B) / (1 - A + B)]
= (2 - A) / (A + B)
1.log14 7=a,log14 5=b,则用a,b表示log35 28=
1.已知:log14^7=a,14^b=5,用a,b表示log35^28
log14(7)=a,log14(5)=b,则用a,b表示log35(28)=?
高一对数运算 已知log14^7=a,log14^5=b,求log35^28 请一定要看我的解法:log35^28可分为
已知 log2 3=a,log3 7=b,试用a,b表示log14 56
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