求值:-log2log2√√√2 ,log4 (8)-log1/9 (3)-log√2 (4) ; (log4(3))*
来源:学生作业帮 编辑:神马作文网作业帮 分类:数学作业 时间:2024/09/24 00:27:19
求值:-log2log2√√√2 ,log4 (8)-log1/9 (3)-log√2 (4) ; (log4(3))*(log9(25))*(log5(8))
-log2log2√√√2
=-log2 log2 2的1/8次幂
=-log2 (1/8)
=log2 8
=3
log4 (8)-log1/9 (3)-log√2 (4)
=log4 4的(3/2)次幂 - 1÷[log3 (1/9)] - log√2 √2的4次幂
=3/2 - 1÷[log3 (3的-2次幂)] - 4
=3/2 + 1/2 -4
=2
(log4(3))*(log9(25))*(log5(8))
=(lg3/lg4)*(lg25/lg9)*(lg8/lg5)
=lg3/(2lg2)*(lg5/lg3)*(3lg2/lg5)
=3/2
=-log2 log2 2的1/8次幂
=-log2 (1/8)
=log2 8
=3
log4 (8)-log1/9 (3)-log√2 (4)
=log4 4的(3/2)次幂 - 1÷[log3 (1/9)] - log√2 √2的4次幂
=3/2 - 1÷[log3 (3的-2次幂)] - 4
=3/2 + 1/2 -4
=2
(log4(3))*(log9(25))*(log5(8))
=(lg3/lg4)*(lg25/lg9)*(lg8/lg5)
=lg3/(2lg2)*(lg5/lg3)*(3lg2/lg5)
=3/2
数学题计算log4 8-log1/9 3+log根号2 1/4
log4 8-log1/9 3=log 根号2 1/4怎么算
计算:(log4 9+log8 3)(log3 2+log9 2)-log1/3 4√81
(log4(3)+log8(3))*(log3(2)+log8(2))-log1/2(^4√32)=?
各位大神log4(3)log9(2)-log1/2(4√32)怎做啊?
log√3^9+log9^27+(1/4)log4^1/16
(log2(5)+log4(125))(log3(2)/log√3(5))怎么解?
比较log1/2(1/3)和log4(8)的大小.
log4(1+√2+√3)+log4(1+√2-√3)的值等于
log4(x+3)+log1/4(x-3)=log1/4(x-1)+log4(2x+1),说明:
log4(3)-log4(12)-log8(4) =log4(3/12)- log8( 8^(2/3) ) log8(
log的一道数学题log3 1/64×log4 √5×log1/25 27 √5是根号下5 ×是乘号=log3 2^(-