x趋向于无穷大时lim(1+k/x)^x 如何用洛必达法则求解
lim(x趋向于无穷大时)e^(1/x)
x趋向于0,lim(((1+x)^x-1)/(x^2))=1,如何用洛必达法则计算?
LIM(INX)/X趋向于无穷大
lim(x趋向于无穷大时)[x^2/(x^2-1)]^x
lim(x趋向于正无穷大时)(1-1/X)^(x^1/2)
lim(x趋向于无穷大时)cos{ln[1+(2x-1)/x^2]}
lim(x趋向于无穷大时)x^2[1-cos(1/x)]
lim(x趋向于正无穷大时)[sin√(x+1)-sin√x]
lim【(arctan x)*(cos(1/x))】,当x趋向于无穷大时,求极限
如何用洛必达法则求lim x→0+ (sinx)^(k/1+ln x) (k为常数)
lim(x-3/x+1)^x lim趋向无穷大
极限求解lim[(2/π)arctanx]^x (x趋向于正的无穷大)