化简：sin(x+π/3)-√3cos(2π/3-x)+2sin(x-π/3)=

来源：学生作业帮编辑：神马作文网作业帮分类：数学作业时间：2024/11/19 00:13:13

展开得到
原式
=sinx*cosπ/3 +cosx *sinπ/3 - √3 *cos2π/3 *cosx -√3 *sin2π/3*sinx +2sinx*cosπ/3 -2cosx *sinπ/3
=sinx* 1/2 +cosx *√3/2 -√3 *(-1/2) *cosx -√3 *√3/2 *sinx +2sinx *1/2 -2cosx *√3/2
=(1/2 -3/2+1)*sinx +(√3/2 +√3/2 -√3)*cosx
=0

化简2sin^2[(π/4)+x]+根号3（sin^x-cos^x）-1 f(x)=2cos*sin(x+π/3)-^3sin^2x+sinx*cosx 已知函数f(x)= [sin(2π-x)sin(π+x)cos(-x-π)] ／[2cos(π-x)sin(3π-x)] 已知函数f(x)=cos(2x-π/3)+sin^2 x-cos^2 x 已知函数f(x)=cos(2x-π\3)+sin²x-cos²x 化简y=sin^2(x)+2sin(x)cos(x)+3cos^2(x) 已知函数f(x)=(√3sinωx+cosωx)*sin(-3π/2+ωx)（0 已知函数f(x)=2cos(x-π/6)sin(x+π/6)-√3*(sin(x-π/6))^2+sin(x-π/6)c 化简sin(3π-x)cos(x-3/2)cos(4π-x)/tan(x-5π)cos(π/2+x)sin(x-5/2π 化简：1、sin(x-π/3)-cos(x+π/6)+√3cosx=?2、已知,sinα+sinβ=√2/2,求cosα 求导f(x) = cos(3x) * cos(2x) + sin(3x) * sin(2x). sin(x+π/3)+2sin(x-π/3)-根号3cos(2π/3-x)