Cos(180°+α)*sin（α+360°)/sin(-α-180°)*cos(-180°-α)

Cos(180°+α)*sin（α+360°)/sin(-α-180°)*cos(-180°-α) 化简cos(540°-α)sin(α-360°)/sin(-α+180°)cos(180°+α) .[1/cos(-α)+cos(180°+ α )]/[1/sin(540°-α)+sin(360°-α)]=tan^3 化简sin(α+180°)cos(-α)sin(-α-180°) ①sin(α+180°)cos(-α)sin(-α-180°)和②sin³（-α）cos（2π+α）tan（- 若sin(α-360°)-cos(180°-α)=m,则sin(180°+α)·cos(180°-α)等于 求证：(1/sinα-sin(180°+α))/(1/cos(540°-α)+cos(360°-α))=1/(tanα) 化简cos（90°-α）/sin（270°-α）*sin（360°-α）*sin（180°-α） 化简cos^2(-α)-[tan(360°+α)/sin(-α)] 化简,cos²(-α)-tan(360°+α)/sin(-α) 已知sin（360°+α）-cos（180°-α）=m 已知cos(180°+α)=-3/5,则sin(360°-α)的值等于