化简:(1/√2+√4)+(1/√4+√6)+……+(1/(√2n-2)+(√2n))(n为正整数,且n≠2)
来源:学生作业帮 编辑:神马作文网作业帮 分类:数学作业 时间:2024/11/17 14:10:34
化简:(1/√2+√4)+(1/√4+√6)+……+(1/(√2n-2)+(√2n))(n为正整数,且n≠2)
RT,化简:(1/√2+√4)+(1/√4+√6)+……+(1/(√2n-2)+(√2n))(n为正整数,且n≠2)
坐等.
RT,化简:(1/√2+√4)+(1/√4+√6)+……+(1/(√2n-2)+(√2n))(n为正整数,且n≠2)
坐等.
(1/√2+√4)+(1/√4+√6)+……+(1/(√2n-2)+(√2n))
=(√2-√4)/[(√2+√4)(√2-√4)]+(√4-√6)/[(√4+√6)(√4-√6)]+
……+(√2n-2-√2n)/[(√2n-2+√2n)(√2n-2-√2n)]
=(√2-√4)/(-2)+(√4-√6)/(-2)+……+(√2n-2-√2n)/(-2)
=(-½)×(√2-√4+√4-√6+……+√2n-2-√2n)
=(-½)×(√2-√2n)
=(√2-√4)/[(√2+√4)(√2-√4)]+(√4-√6)/[(√4+√6)(√4-√6)]+
……+(√2n-2-√2n)/[(√2n-2+√2n)(√2n-2-√2n)]
=(√2-√4)/(-2)+(√4-√6)/(-2)+……+(√2n-2-√2n)/(-2)
=(-½)×(√2-√4+√4-√6+……+√2n-2-√2n)
=(-½)×(√2-√2n)
化简:(1/√2+√4)+(1/√4+√6)+……+(1/(√2n-2)+(√2n))(n为正整数,且n≠2)
3)1-2+3-4+5-6+…+(-1)^n+1 n(n为正整数)
1-2 -4 -6…+(-1n+1次方)·n(n为正整数)
1-2+3-4+5-6+……+(-1)n+1n(n为正整数 n+1在上面)
若n为正整数,求1/n(n+1)+1/(n+1)(n+2)+1/(n+2)(n+3)+1/(n+3)(n+4)+.+1/
1*2+2*3+3*4+4*5+…+n(n+1)(n为正整数)
[(√n^2-1)+(√n^2-4)+(√n^2-9)+……(√n^2-(n-1)^2)]/n^2
1\n(n+3)+1\(n+3)(n+6)+1\(n+6)(n+9)=1\2 n+18 n为正整数,求n的值
limn→∞n√(1+1/n)(1+2/n)...(1+n/n)等于多少?
n为正整数,f(n)为正整数,f(n)为n的增函数.f[f(n)]=2n+1,求证:4/3
已知888个连续正整数之和:n+(n+1)+(n+2)+(n+3)+(n+4)+(n+5)+(n+6)+(n+7)+··
设n为正整数,证明:6 | n(n + 1)(2n +1).