数列an=(3n-1)/n,求极限
数列an=(3n-1)/n,求极限
在数列{an}中,an=1/n(n+1)(n+2),求Sn的极限
数列极限(已知lim[(2n-1)an]=2,求lim n*an)
数列an的通项公式为an=(n-1)/(2n+3),求它的极限
Xn=[(n-1)/(n+1)]^n 求数列极限
数列极限的运算lim an/(an+1) =2 求lim 2anlim (2n+1)*an=3 求lim n*an
数列an,第n+1项=根号下(第n项+1)求数列极限
数列{an},a1=1,an+1=2an-n^2+3n,求{an}.
求数列xn=n/n+1的极限
已知an=5n(n+1)(n+2)(n+3),求数列{an}的前n项和Sn
lim n →∞ (1^n+3^n+2^n)^1/n,求数列极限
已知数列{an}的通项公式是an=5/2^n-7/(n^2+3n+2)求an各项和的极限