1.xy=6,x²+y²=12,x与y相等吗?
来源:学生作业帮 编辑:神马作文网作业帮 分类:数学作业 时间:2024/11/19 21:12:38
1.xy=6,x²+y²=12,x与y相等吗?
2.x+y=6,xy=z²+9,求x,y,z的值.
3.若a-b=8,ab+c²+16=0,求证a+b+c=0.
4.若x²+2x+y²-8y+17=0,求x,y的值.
2.x+y=6,xy=z²+9,求x,y,z的值.
3.若a-b=8,ab+c²+16=0,求证a+b+c=0.
4.若x²+2x+y²-8y+17=0,求x,y的值.
1.相等y=6/x x^2+(6/x)^2=12 解得x^2=6,y^2=6 xy=6 x=y
2.x=3 y=3 z=0 x=6-y
(6-y)y=z^2+9
6y-y^2=z^2+9
y^2-6y+9+z^2=0
(y-3)^2+z^2=0
y=3,z=0
x=3
3.a=b+8
(b+8)b+c^2+16=0
b^2+8b+16+c^2=0
(b+4)^2+c^2=0
b=-4 c=0 a=4
a+b+c=0
4.x^2+2x+1+y^2-8y+16=0
(x+1)^2+(y-4)^2=0
x=-1 y=4
2.x=3 y=3 z=0 x=6-y
(6-y)y=z^2+9
6y-y^2=z^2+9
y^2-6y+9+z^2=0
(y-3)^2+z^2=0
y=3,z=0
x=3
3.a=b+8
(b+8)b+c^2+16=0
b^2+8b+16+c^2=0
(b+4)^2+c^2=0
b=-4 c=0 a=4
a+b+c=0
4.x^2+2x+1+y^2-8y+16=0
(x+1)^2+(y-4)^2=0
x=-1 y=4
1.xy=6,x²+y²=12,x与y相等吗?
已知x²+y²-8x+6y+25=0,求(x-y+4xy/x-y)(x+y-4xy/x+y)
x/xy-y²与y/x²-xy 通分
1.x-y=16,xy=6,求3x²y-6xy²+18y+6
1.设A=2x²-3xy+y²-x+2y,B=4x²-6xy+2y²-3x-y,
1.设A=2x²-3xy+y²+x-3y,B=4x²-6xy+2y²+4x-y,
已知x²-xy,xy-y²=-12,分别求式子x²-y²与x²-2xy
已知x/y=2,求x²-xy+3y²/x²+xy+6y²的值
已知x+y=0.2,x+3y=1.求3X²+12XY+12Y²
已知x/y=2,求2x(x+y)-y(x+y)/4x²-4xy+y²
已知(x+y)²=1 (x-y)²=49,求x²+y²与xy的值
(x+y)²=1,(x-y)²=49,求x²+y²与xy的值