18x=2*18(28—x)怎么解
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18级的xiaozhaotaitai和464629593,你们真的检验过吗?太不负责任了吧~(2x-3/x)^2+5+12x=18/x(2x-3/x)^2+12x-18/x+5=0(2x-3/x)^2
x+x+3=92x=6x=312x(是乘)(x+6)=144x+6=12x=63x(是乘)(x-3)=18x-3=6x=94x(乘)2+2x(是乘)(x-3)=408+2x-6=40x=197x+2x
1,(1)将(x+3/x-1)设为a(2)得a²-5a+6=0(3)因式分解(a-2)(a-3)=0(4)a1=2a2=32,化简得x³-4x²+18=0
原式:X^2-5X+6+18=X^2+10X+9-5X+24=10X+915X=15X=1
28+1.9X=4(6+0.6X)X+250×18=2(X+120×18)28+1.9x=24+2.4xx+4500=2(x+2160)1.9x-2.4x=24-28x+4500=2x+4320-0.
(X-X*20%-18)-(X-X*20%-18)*10%=X*1/2-3则(X*80%-18)*90%=X*1/2-372%*X-16.2=X*1/2-322%*X=13.2X=60
拆项法,利用1/x(x+3)=1/3[1/x-1/(x+3)],方程化为:1/3[1/x-1/(x+3)+1/(x+3)-1/(x+6)+1/(x+6)-1/(x+9)]=3/(2x+18)1/3[1
(2x-3/x)²+6(2x-3/x)+5=0(2x-3/x+5)(2x-3/x+1)=02x-3/x+5=02x-3/x+1=02x²+5x-3=02x²+x-3=0(
1/x(x+3)+1/(x+3)(x+6)+1/(x+6)(x+9)=3/2(x+9)(1/3)×[3/x(x+3)+3/(x+3)(x+6)+3/(x+6)(x+9)]=3/2(x+9)(1/3)[
10(x+2)+x-18=10x+x+2x11x+2=13x2x=2x=1
(x-3)(x-2)+18=(x+3)(x+3)x^2-5x+6+18=x^2+6x+911x=15x=15/11
6x-2(340-3x)=2206x-680+6x=2206x+6x=680+22012x=900x=7518+0.4x=22.2-x0.4x+x=22.2-181.4x=4.2x=3
设x1=4-√3,x2=4+√3,是方程X^2-8X+13=0的两根所以X1^2-8X1+15=2X^4-6X^3-2X^2+18X+23=(X+1)^2*(X^2-8X+13)+10=10所以原式=
1/x(x+3)+1/(x+3)(x+6)+1/(x+6)(x+9)=[1/x-1/(x+3)+1/(x+3)-1/(x+6)+1(x+6)-1/(x+9)]/3=[1/x-1/(x+9)]/3=3/
15x平方-18x+9-(-3x平方+19x-31)-8x=18x²-45x+40=9(2x²-5x+5)-5=9×0-5=-5
x(x^2-1)+2x^2*(x+1)-3x*(2x-5)=x(3x^2-4x)-28;x^3-x+2x^3+2x^2-6x^2+15x=3x^3-4x^2-28;14x=-28.x=-2.
4x+2=2x+182x=16x=8
问题是不是X2=(X+30)*(X-18)啊?要是上面的话就这样X2=X*X-X*18+30*X-30*18=X2+12X-540移项得:X2-X2-12X=-540,即-12X=-540,X=45*
再答:望采纳,谢谢
方程右边的1减到左边来,再同分得到(6x-2)/(x^2-x)=0得到x=1/3这个方程即使两边乘以x^2-x,x的最高次数为2次,也不会出现x^3,你肯定是什么地方弄错了