[2x(x的平方y-xy的平方) xy(xy-x的平方)]÷xy-搜答案-神马作文网

（x的平方+2xy+y的平方）（x的平方-xy+y的平方）的平方=（x²+2xy+y²）（x²-xy+y²）²=（x+y)²(x²

=(2xy-x+y)(2xy-x-y)

再问：过程有木有

1、原式=[2x/(x^2-1)]-[(x+1)/(x^2-1)]=[2x-(x+1)]/(x^2-1)=(x-1)/(x^2-1)=(x-1)/[(x+1)(x-1)]=1/(x+1)2、原式=[x

y/(x²-xy)+2/(y-x)-x/(y²-xy)=[y²+2(-xy)+x²]/(x²y-xy²)=(x-y)²/[(x-y

x²-y²=(x+y)(x-y)所以最简公分母(x+y)²(x-y)所以2xy/(x+y)²=2xy(x-y)/(x+y)²(x-y)x/(x&sup

2xy/(x+y)的平方=2xy(x-y)/(x+y)²(x-y)x/x的平方-y的平方=x(x+y)/(x+y)²(x-y)

2x(-xy)^2-x^2(x^2y^2-y^2)=(xy)^2(2x-x^2+1)

2xy/(y的平方/x)

2xy/(y^2/x)=2xy÷(y^2/x)=2xy×(x/y^2)=2x^2/y再问：O(∩_∩)O谢谢

我不知道你题目有没有差错,但解题步骤是一样的XY-2的平方=12推出xy=根号12+2再由X平方-XY=21推出X然后已知XXY接着推出Y后面的问题只要带进去就行了

(（x-y）(x-y))/((x-y)(x+y))=(x-y)/(x+y).

x的平方-2xy/xy-2y的平方＝x(x-2y)/y(x-2y)=x/y

原式=-(x²+2xy+y²)=-(x+y)²

2xy-x^2-y^2=-(x^2-2xy+y^2)=-(x-y)^2

原式(-xy/3)²*[xy(2x-y)-2x(xy-y²)]=(x²y²/9)(2x²y-xy²-2x²y+2xy²)

2xy×(-x的平方y)

解2xy×(-x²y)=-2x³y²a³b²/3×(-3ab²/2)²——这个吗=a³b²/3×(9a

(x²+xy)/(x+y)²=x(x+y)/(x+y)²=x/(x+y)2xy/(x+y)²x/(x²-y²)∵最简公分母为：(x+y)&#

a(x²+2xy+y²)-b（x²-y²）=a（x+y）²-b（x+y）（x-y）=（x+y）（ax+ay-bx+by）再问：你确定对吗？和我已开始算

x的平方-2xy+y的平方-4=(x-y)²-2²=(x-y+2)(x-y-2)再问：(3a-7)的平方-(a+5)的平方这个呢？再答：(3a-7)的平方-(a+5)的平方=(3a

(x平方+2xy+y的平方）/（x+y)=（x+y)²/(x+y)=x+y