y=[2m 4]x [3-n]m,n是什么数,函数图像经过原点
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/22 06:45:54
xy属于N因为x属于M,y属于N可设x=3m+1,y=3n+2则xy=(3m+1)*(3n+2)=9mn+6m+3n+2=3(3mn+2m+n)+2由于m,n均属于Z,则3mn+2m+n属于Z显然xy
[x-(m+3)]^2+[y+(1-4m^2)]^2=-16m^4-9+(m+3)^2+(1-4m^2)^2所以r^2=-16m^4-9+(x+3)^2+(1-4m^2)^2>0-16m^4-9+(m
2x(M+3x)=6x²y²+N2xM+6x²=6x²y²+N所以N=6x²,且2xM=6x²y²,即M=3xy&sup
圆的方程化为[x-(m+3)]2+[y-(1-4m2)]2=1+6m-7m2,则有1+6m-7m2>0,解得-17<m<1,故m的取值范围是(-17,1).
(1)由方程x2+y2-2(m+3)x+2(1-4m2)y+16m4+9=0变形得:[x-(m+3)]2+[y+(1-4m2)]2=-7m2+6m+1,当且仅当-7m2+6m+1>0,即7m2-6m-
y=x-3x+1经过点(m,0),代入得到m^2-3m+1=0m^2=3m-1m4-21m+10=(3m-1)^2-21m+10=9m^2-6m+1-21m+10=9m^2-27m+11=9(3m-1
解析2*(M+3x)=2*m+6x=6x²y²+N两边比较2*m=6x²y²m=3x²y²N=6x再问:我没看明白。请问这几个算式都是为什么
3x(M-5x)=6x^2y^3+N,3x*M-15x^2=6x^2y^3+NM=2xy^3N=-15x^2
由于2x(M+3x)=6x^2y^2+N,所以2xM+6x^2=6x^2y^2+N比较可知2xM=6x^2y^2,6x^2=N所以M=3xy^2,N=6x^2
方程两边都乘(x-4),得2=3(x-4)-m∵当最简公分母x-4=0时,方程有增根,∴把x-4=0代入整式方程,∴m=-2.故选A.
1.[(m+n)(n-m)-(m+n)^2+3m(m+n)]÷(-2m)=(m+n)[(n-m)-(m+n)+3m]÷(-2m)=(m+n)(n-m-m-n+3m)÷(-2m)=m(m+n)÷(-2m
9(x+y)^(2m)*(x-y)^(4n)*[-(x+y)^2]=-9(x+y)^(2m+2)*(x-y)^(4n)∴a=92m+2=104n=12-n∴m=4n=12/5
3m=5n+13m-6n=-n+1n=3(2n-m)+1=3(2n-m+1)-2所以可令n=3k+1或者3k-2.
(2m+3n)(2m-n)-4n(2m-n)=(2m-n)(2m+3n-4n)=(2m-n)(2m-n)=(2m-n)^2(x+y)^2(x-y)+(x+y)(y-x)^2=(x+y)(x-y)(x+
[x-(m+3)]^2+[y-(1-4m^2)]^2=-(7m^2-6m-1)=-(7m+1)(m-1)>0-1/7再问:半径是多少再答:根号下[-(7m+1)(m-1)]
(1)由方程x2+y2-2(m+3)x+2(1-4m2)y+16m4+9=0变形得:[x-(m+3)]2+[y+(1-4m2)]2=-7m2+6m+1,要使方程表示圆,则需要-7m2+6m+1>0;如
x^3m=8,y^3n=27,所以x^m=2,y^n=3,所以(x^2m)^3+(y^n)^3-x^2m*y^n=(2^2)^3+3^3-2^2*3=64+9-12=61
x^2n=3x^6n=(x^2n)^3=3^3=27x^4n=(x^2n)^2=3^2=9y^9n=(y^3n)^3=2^3=82x^6n-x^4n×y^3m-y^9m=2*27-9*2-8=28
.3x^m+1y^2与x^3y^n的积是3x^(m+4)y^(2+n),即是单项式3x^5y^5则有m+4=5,n+2=5m=1,n=3n^m+m^n=1+3=4再问:我也是这个答案,但是孩子说老师说