y=ln(5X 1)
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y'=(lnlnx)'/lnlnx=(lnx)'/lnxlnlnx=1/xlnxlnlnx
y=x^5+ln^3xy'=(x^5)’+(ln^3x)‘=5x^4+3(lnx)²/X
你做的是对的y=ln(ln√x)y`=[lh(ln√x)]`=1/ln√x*(ln√x)`=(1/ln√x)*(1/√x)*(√x)`=(1/ln√x)*(1/√x)*(1/2)/√x=1/(2xln
y'=1/tanx*(tanx)'=1/tanx*1/(cosx)^2=1/(sinxcosx)=2/sin2x
复合函数f(x)=lnxg(x)=ln[ln(x)]r(x)=ln{lnln(x)]}r'(x)=[1/lnln(x)]g'(x)=[1/lnln(x)][1/ln(x)]f'(x)=[1/lnln(
表示以e为底的对数函数符号
1.y‘=(e^(-5x^2))'tan3x+e^(-5x^2)(tan3x)'=-10xe^(-5x^2))'tan3x+3e^(-5x^2)(sec3x)^22.y'=cosx/(sinxlnsi
y=(ln(ln(x))'/ln(ln(x))=(ln(x))'/(ln(x)(ln(ln(x)))=1/(xln(x)ln(ln(x)))
答:y=ln(-x)y'(x)=[1/(-x)]*(-1)=1/x所以:y=ln(-x)的导数为y'(x)=1/x再问:非常感谢,,,那y=ln(3x+2)的导和y=ln(4x+2)的导分别怎么算呢?
是y=lnx/sinx?y'=(sinx/x-cosxlnx)/sin^2x
y=ln(tanx)/ln(sinx)dy/dx=[lnsinx.d/dx(lntanx)-lntanxd/dx(lnsinx)]/[ln(sinx)]^2=[lnsinx.(1/tanx)(secx
y=2ln(lnx)dy=y'dx=(2/lnx)*(1/x)dx=2/xlnxdx
y=e^c·x^(-1/3)
y=ln(sinx)y'=cosx/sinx=cotxy''=-1/sin²x∴y''=-1/sin²xdy=cotxdx
y=ln(1-x)y'=[1/(1-x)]*(1-x)'=-1/(1-x)14382希望对你有帮助!
y'=(a^x)'=a^xlnxy'=(x^a)'=ax^(a-1)y=(sin5x)^(lnx)y'=[(sin5x)^lnx]·ln(lnx)·(1/x)+lnx(sin5x)^(lnx-1)·5
y=ln(2x+5),则dy=2/(2x+5)dx
y'=[ln(3x+5)]'=[1/(3x+5)]*(3x+5)'=3/(3x+5)