Y=2x 1 10Y X=2(10X Y)怎么解过程

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Y=2x 1 10Y X=2(10X Y)怎么解过程
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai

(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=4x-2y-z-5x[6y-(x+y)]+x-(3y-10z)=4x-2y-z-30xy+5x²+5xy+x-3

{ x-y/7-x+y/10=1/2 {2(x-y)+5(x+y)=3

x-y/7-x+y/10=1/2两边乘7010x-10y-7x-7y=353x-17y=35(1)2(x-y)+5(x+y)=32x-2y+5x+5y=37x+3y=3(2)(2)*3-(1)*79y

y'-2y=(e^x)-x

首先求齐次方程通y'-2y=0特征方程:x-2=0x=2为特征根∴y=Ce^(2x)设方程的一个特解为y=Ae^x+ax+b代入方程:Ae^x+a-2Ae^x-2ax-2b=-Ae^x-2ax+a-2

已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y

先化简[(x²+y²)-(x-y)²+2y(x-y)]/4y[(x²+y²)-(x-y)²+2y(x-y)]/4y=[x²+y&s

已知x-y-3绝对值+(2x+2y+10)的平方=0,则(x+y)(x-Y)=

x-y-3绝对值+(2x+2y+10)的平方=0X-Y-3=0X-Y=32X+2Y+10=0X+Y=-5(x+y)(x-Y)=3X(-5)=-15

数学题已知p=x^/x-y-y^/x-y,q=(x+y)^-2Y(X+Y),

你的题是什么意思?“^/”是什么意思?

已知X-Y/X+Y=3,求代数式2(x-y)/X+Y-3X+Y/X+Y

X+Y分之X-Y等于3x=-2yX+Y分之2(x-y)减X+Y分之3X+Y=(-x-3y)/(x+y)=1

已知x,y满足约束条件{2x+5y>=10,2x-3y>=-6,2x+y

在坐标系中先作2x+5y≥10对应的直线2x+5y=10,取直线上方区域;然后作2x-3y≥-6对应的直线2x-3y=-6,把y的系数变为正,可知取直线下方区域;最后作2x+y≤10对应的直线2x+y

解方程组:(x+3)(y-2)=(x-3)(y+10),(x+1)(y+3)=(x-2)(y+12)

.死算呗xy-2x+3y-6=xy+10x-3y-30,2x-y=4xy+3x+y+3=xy+12x-2y-24,3x-y=92式减1式,x=5,y=6

已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)

因为(x-y)/(x+y)=3,则(x+y)/(x-y)=1/3则5(x-y)(x+y)-(x+y)/2(x-y)=5*3-1/(3*2)=15-1/6=89/6

解方程组:2/(x+y)+5/(x-y)=18 9/(x+y)-10/(y-x)=66

2/(x+y)+5/(x-y)=189/(x+y)-10/(y-x)=66设x+y=a,x-y=b,原方程化为2/a+5/b=18-----1(1)9/a+10/b=66-------(2)(2)-(

[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x其中x=2012 y=2013

先一个一个的展开括号项,再同项合并就行了啊[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x=[xx-xy-(xy-yy)+x(x-y)+y(x-y)]÷2x=[xx-xy-xy+yy+xx-

已知2x-y=10,求式子[(x^2+y^2)-(x-y)^2+2y(x-y)]/4y (4xy-2y²)/4

已知2x-y=10,式子[(x^2+y^2)-(x-y)^2+2y(x-y)]/4y=[x^2+y^2-x^2+2xy-y^2+2xy-2y^2]/4y=[4xy-2y^2]/4y=2y(2x-y)/

解方程组:2/(x+y)+5/(x-y)=18 9/(x+y)-10/(y-x)=66

另a=1/(x+y),b=1/(x-y);则2a+5b=18;9a+10b=66;解得a=6,b=6/5;即       &nbs

已知x^2+y^2--6x--2y+10=0,求x+y/x--y

x^2+y^2-6x-2y+10=0x^2-6x+9+y^2-2y+1=0(x-3)^2+(y-1)^2=0x=3,y=1(x+y)/(x-y)=4/2=2

已知x^2-2x+y^2+6y+10=0,求分式x-y/x+y的值

x^2-2x+y^2+6y+10=0(x-1)^2+(y+3)^2=0x=1y=-3(x-y)/(x+y)=4/(-2)=-2

解方程组 2x+y(y-2x)=9 (x+y)(x+y-3)=10

设X+Y=A,则由a(a-3)=10得出(a-5)(a+2)=0,得a=5或a=-2.然后再分2种情况分别代入前面方程式.就能求出X、Y分别是多少了我觉得我这方法是最好解的方法了.