x加y等于8,10y加y减{10x加y}等于18.
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(Y+1)/(Y-1)=XY+1=X(Y-1)XY-Y=2Y(X-1)=2Y=2/(X-1)再问:XY-Y=2你这一步错了,不过提醒我做法了Y+1=XY-X1+X=XY-Y1+X=Y(X-1)Y=(1
x^2-2x+y^2+6y+10=0x^2-2x+1+y^2+6y+9=0(x-1)^2+(y+3)^2=0x-1=0,y+3=0x=1,y=-3(x-y)/(x+y)=4/(-2)=-2
x-y=-2①x+y=1②把①+②得x-y+x+y=-2+12x=-1x=-1/2把x=-1/2代入②得(-1/2)+y=1y=1-(-1/2)=3/2∴x=-1/2,y=3/2即x=-0.5,y=1
x^2+y^2-2x+6y+10=0(x-1)^2+(x+9)^2=0欲等式成立x=1,y=-9于是x+y=-8
|x|+x+y=10|y|+x-y=12设y为正数|y|+x-y=12y+x-y=12x=12|x|+x+y=102x+y=10y=-14不合题意,舍去设x,为正数,y为负数|x|+x+y=102x+
即|x-1|+(y-2)²=0所以x-1=0,y-2=0x=1,y=2所以原式=(1+2)^(1-2)=1/3
3x-2y=8(1)2x+3y=1(2)(1)×3+(2)×29x+4x=24+213x=26所以x=2y=(3x-8)/2=-1
题在哪
x²+y²-8x-10y+41=0(x²-8x+16)+(y²-10y+25)=0(x-4)²+(y-5)²=0平方大于等于0,相加等于0,
后半句意思都没表达清楚求采纳
根号x减24的平方加y加8的绝对值等于0x-24=0y+8=0所以x+y=16
x=8,y=15.(诚心为你解答,给个好评吧)
x^2-y^2=(x+y)*(x-y)=-1*(-3)=3
31,x=7,y=1.
题:8x+y-z=82x-y+z=18求8x+y+z原方程组变形为:8x+y=z+8……①2x-y=-z+18……②①+②得:10x=26x=13/5……③①-②×4得:5y=5z-64y=z-64/
x+y=19x-y=8.6两式相加2x=27.6x=13.8y=5.2
X+y=55X-y=13X=3y=5再答:点错了y=2
(x-y)(x+y)+(x-y)(x+y)=2*(x-y)(x+y)=2(x^2-y^2)=2x^2-2y^2
这个要分类讨论的,有四个,(1),当x>0,y>0时.2x+y=10,y+x-y=12..所以x=12.y=-14.x+y=-2不可能(2),当x>0.y
x+y=8①2.5x-2(x+y)=-1②①代入②,得2.5x-2×8=-12.5x=15x=6所以y=8-x=8-6=2即x=6y=2