x减1分之x减x加1除以1减x分之4x的平方减4x加1-搜答案-神马作文网

1楼最后算错了引用一下：1/(x+1)-1/(x²-1)÷(x+1)/(x²-2x+1)=1/(x+1)-1/(x+1)(x-1)×(x-1)(x-1)/(x+1)=1/(x+1)

原式=(x^2-1)/x÷(x^2+x)/x^2=(x-1)(x+1)/x*x^2/x(x+1)=x-1当x=2时,原式=2-1=1

X-(X-1)/2=1+(X+2)/5两边乘以1010X-5(X-1)=10+2(X+2)3X=9X=3

x减2分之x加1加x加1分之1等于1方程两边同时乘以(x-2)(x+1),得(x+1)²+(x-2)=(x-2)(x+1)则x²+2x+1+x-2=x²-x-2则4x=-

1/x+1/y=2(x+y)/xy=2x+y=2xy(2x-xy+2y)/(3x+5xy+3y)=[2(x+y)-xy]/[3(x+y)+5xy]=(4xy-xy)/(6xy+5xy)=3xy/11x

(x+1)(x+2)/(x²+4x+4)×(3x+6)/(2x²-8)×6÷1/(x²-4)=(x+1)(x+2)/(x+2)²×2(x+2)/2(x+2)(x

[x/(x+3)+6x/(x+3)(x-3)]×(x+3)(x-3)=x(x-3)+6x=x-3x+6x=x+3x

(x+1)分之1-(x²-6x+9)分之(3-x)÷(x-3)分之(x²+x)=(x+1)分之1-(x-3)²分之[-(x-3)]÷(x-3)分之[x(x+1)]=(x+

x=-1/3

看你的题目都看了很少时间(x-4)/(x^2-1)÷(x^2-3x-4)/(x^2+2x+1)+1/(x-1)=(x-4)/(x^2-1)[(x^2+2x+1)/(x^2-3x-4)]+1/(x-1)

原式=(x+1)/x÷(2x²-1-x²)/2x=(x+1)/x÷(x²-1)/2x=(x+1)/x÷(x+1)(x-1)/2x=(x+1)/x*2x/(x+1)(x-1

[(x+2)/(x-2)-(x-4)/(x^2-4x+4)]÷(x^2-1)/(x^2+x)=[(x^2-4)/(x-2)^2-(x-4)/(x-2)^2]*x(x+1)/(x-1)(x+1)=(x^

是(x-1)/(x-2+1)=3吗x-1=3x-3无解

再问：呵呵你写错了再问：是2分之x

(x²+x-2)分之(1+x)÷[x-2+(x+2)分之3]=(x²+x-2)分之(1+x)÷[(x+2)分之(x²-1)]=[(x+2)(x-1)]分之(1+x)×(x

√x－1／√x＝3两边平方得出x＋1／x＝11(1+xˆ2)∕x=x＋1／x＝11

你可以手写照下来吗?看不懂再答：再问：再问：你能放大点吗再问：人呢再答：哦，我再写一遍再问：嗯再答：再问：图片好小再问：不过基本会了

/>（2x-x分之1+x的平方）除以x分之x-1,其中x=根号2=[2x²-(1+x²)]/x÷(x-1)/x=(x²-1)/(x-1)=(x-1)(x+1)/(x-1)