x³y-2x²y xy

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x³y-2x²y xy
x/x-y*y^2/x+y-x^3y2/x^4-y^4/x^2/x^2+y^2

写清楚点点比如说前面是X/X还是X/(X-Y)打上括号分段这样才能清楚的做

若正数x,y满足2x+y-3=0,则x+2yxy的最小值为(  )

∵正数x,y满足2x+y-3=0,∴3=2x+y.∴x+2yxy=13(2x+y)(1y+2x)=13(5+2xy+2yx)≥13(5+22xy•2yx)=3,当且仅当x=y=1时取等号.则x+2yx

已知x和y满足2x+3y=5,则当x=4时,代数式3(xXx)+12xy+(yXy)的值是( )

2x+3y=53y=5-2xy=(5-2x)/33x^2+12xy+y^2=3x^2+12x(5-2x)/3+(5-2x)^2/9x=4时=48-48+1=1

已知x/5=y/3,则(x/x+y)+(y/x-y)-(yxy/xxx-yxy)

y=3x/5原式=x/(x+3x/5)+(3x/5)/[x-3x/5]-(9x^3/25)/(x^3-9x^3/25)=8/3-3/2-9/16=29/48

X+y=4,Xy=-12 求(1)XxX+yxy (2)XxXxy+Xxyxy

(1)XxX+yxy=(x+y)^2-2xy=4^2+2*12=16+28=44(2)XxXxy+Xxyxy=xy*(x+y)=4*(-12)=-48不懂可追问,有帮助请采纳,谢谢!

x^2-y^2/x+y-4x(x-y)+y^2/2x-y,

(x^2-y^2)/(x+y)-(4x(x-y)+y^2)/(2x-y)=(x-y)(x+y)/(x+y)-(4x^2-4xy+y^2)/(2x-y)=(x-y)-(2x-y)^2/(2x-y)=(x

因式分解3x^2(x-y)+6x(y-x)

3x^2(x-y)+6x(y-x)=3x^2(x-y)-6x(x-y)=(x-y)(3x^2-6x)=3x(x-y)(x-2)

英语翻译在驾照的最后两行字XXXX-XXX(X代表数字) seymour st vancouver BC YXY XYX

seymourst(seymour街名)st(street的缩写)vancouver(加拿大的省名)(温哥华)再问:谢谢谢谢,请问前面和后面的数字和字母是什么意思啊再答:前面的数字是门号,后面的号码及

1、x(x-y)(x+y)-x(x+y)^2

1)x(x-y)(x+y)-x(x+y)^2=x((x-y)(x+y)-(x+y)^2)=x(x^2-y^2-x^2-2xy-y^2)=x(-2xy-2y^2)=-2xy(x+y)2)(2a+b)(2

【(x-y)^2+(x+y)(x-y)】除以 2x

【(x-y)^2+(x+y)(x-y)】除以2x=(x-y)*(x-y+x+y)/2x=(x-y)*2x/2x=x-y

[(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y

[(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y=[x²-y²-x²-2xy-y²-xy+xy²]/(y/2)=[(x-2)y

[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x其中x=2012 y=2013

先一个一个的展开括号项,再同项合并就行了啊[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x=[xx-xy-(xy-yy)+x(x-y)+y(x-y)]÷2x=[xx-xy-xy+yy+xx-

化简:(x-3y)(x+y)-(x-2y)(x+2y)-(x-y)平方

(x-3y)(x+y)-(x-2y)(x+2y)-(x-y)平方=x²-2xy-3y²-x²+4y²-x²+2xy-y²=(x²-

已知|3-y|+|x+y|=0,求x+yxy

|3-y|+|x+y|=0,且|3-y|≥0,|x+y|≥0,所以3-y=0,x+y=0,所以y=3,x=-3.所以x+yxy=-3+3-3×3=0-9=0.答:x+yxy的值为0.

在分式2x+3yxy中,x、y的值都扩大到原来的2倍,则分式的值(  )

分式2x+3yxy中,x、y的值都扩大到原来的2倍,则分式的值缩小为原来的12,故选:B.

[(3x+y)(x-y)-(2x+3y)(x-y)]*(x-y)

=(x-y)[(3x+y)-(2x+3y)]*(x-y)=(x-y)*(x-y)(3x+y-2x-3y)=(x-y)(x-y)(x-2y)到底是化简,还是?=(x*x-2xy+y*y)(x-2y)=x

(1)(x^2/x)-y-x-y

(1)x^2/x)-y-x-y=x-y-x-y=-2y(2)(a/a-b)-(a/a+b)-(2b^2/a^2-b^2)=a(a+b-a+b)/(a^2-b^2)-(2b^2/a^2-b^2)=2b/

【x-3y][x+y]-[x-2y][x +2y]-[x-y

解题思路:根据题意,由整式的运算的知识整理,分析可以求得解题过程:

有这样一道题:"计算(2*x*x*x-3*x*x*y-2*x*y*y)-(x*x*x-2*x*y*y+y*y*y)+【-

解代数式得:-3x的平方y-2y的三次方因为1/2的平方=-1/2的平方,所以结果仍正确给分吧!嘿嘿!

(x+y)^2(x-y)^2-(x-y)(x+y)(x^2+y^2)分解因式

原式=(x+y)(x-y)[(x+y)(x-y)-(x²+y²)]=(x+y)(x-y)(x²-y²-x²-y²)=-2y²(x+