x²-4y² x 2y分解因式
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x²-4y²+x-2y=(x²-4y²)+(x-2y)=(x-2y)(x+2y)+(x-2y)=(x-2y)(x+2y+1)很高兴为您解答,祝你学习进步!【学习
:-x²-4y²+4xy=-(x²+4y²-4xy)=-(x-2y)²施主,我看你骨骼清奇,器宇轩昂,且有慧根,乃是万中无一的武林奇才.潜心修习,将来
平方差公式!x^4+y^4=(x²+iy²)(x²-iy²)=(x+i√iy)(x-i√iy)(x+√iy)(x-√iy)
(1-x^2)(1-y^2)+4xy=1-x²-y²+x²y²+4xy=(x²y²+2xy+1)-(x²-2xy+y²)
3x2(a+3)-4x2y(a+3)=x2(a+3)(3-4y),当a=-0.5,x=3,y=1时,原式=32×(-0.5+3)×(3-4×1)=-22.5.
(1)2x2y-8y=2y(x2-4)=2y(x+2)(x-2).(2)(x-y)2-2x+2y+1=(x-y)2-2(x-y)+1=(x-y-1)2.
∵代数式x3+y3+3x2y+axy2含有因式x-y,∴当x=y时,x3+y3+3x2y+axy2=0,∴令x=y,即x3+x3+3x3+ax3=0,则有5+a=0,解得a=-5.将a=-5代入x3+
(2x+1/2y)(2x-1/2y)
x3-4x2y+4xy2,=x(x2-4xy+4y2),=x(x-2y)2.
x^2-x-4y^2+2y=(x^2-4y^2)-(x-2y)=(x+2y)(x-2y)-(x-2y)=(x-2y)(x+2y-1)
原式=y(x2+2x+1)=y(x+1)2,故答案为:y(x+1)2.
=7x²-4x²+4xy-y²=7x²-(2x-y)²=(√7x+2x-y)(√7x-2x+y)本题答案不唯一的
8x2y-8xy+2y,=2y(4x2-4x+1),=2y(2x-1)2.
=[2(a-b)]^2-(x-y)^2=(2a-2b+x-y)(2a-2b-x+y)
你的式子是无法分解的,已经是最简代数式了x^2-xy+y^2=(x-y/2)^2+3y^2/4恒大于0,无法分解
x²-4y²=x²-(2y)²=(x+2y)(x-2y)这里用到了平方差公式.很高兴为您解答,祝你学习进步!如果我的回答对你有帮助,请及时选为满意答案,谢谢~~
x^4-y^4+4x^2+4(分组分解法)=(x^4+4x^2+4)-y^4=(x^2+2)^2-y^4(公式法)=(x^2+2+y^2+2)(x^2-y^2+2)(公式法)4x^2-12xy-c^2
(x+y)^4+(x+y)^2-20=[﹙x+y﹚²+5﹚][﹙x+y﹚²-4]=﹙x²+2xy+y²+5﹚﹙x+y-2﹚﹙x+y+2﹚
x2y-2xy-y=y(x2-2x-1)=y(x2-2x+1-2)=y[(x-1)2-(2)2]=y(x-1+2)(x-1-2),故答案为:y(x-1+2)(x-1-2).
用提取公因式法,提取(x+3y)原式=(x+3y)[(3x-4y)-(x-2y)]=(x+3y)(2x-2y)=2(x+3y)(x-y)