x² y² xy-y 3=0

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x² y² xy-y 3=0
若2x+y=0,则代数式4x3+2xy(x+y)+y3的值为______.

∵2x+y=0,∴4x3+2xy(x+y)+y3=2x[2x2+y(x+y)]+y3=2x[x(2x+y)+y2]+y3=2xy2+y3=y2(2x+y)=0.故答案为:0.

已知x+y=10,xy=24,求x3+y3-x2y-xy2的值

x3+y3-x2y-xy2=(x+y)(x2-xy+y2)-xy(x+y)=(x+y)(x2-2xy+y2)=(x+y)(x2+2xy+y2-4xy)=(x+y)[(x+y)2-4xy]=10×(10

已知x+y=1,求x3+y3+3xy的值.

∵x+y=1,∴x3+y3+3xy=(x+y)(x2-xy+y2)+3xy=x2+y2+2xy=(x+y)2=1.

已知X+Y大于0,比较X3次方+Y3次方与X平方Y+XY平方的大小

x^3+y^3-x^2y-xy^2=x^2(x-y)-y^2(x-y)=(x^2-y^2)(x-y)=(x+y)(x-y)^2,因为x+y大于0,(x-y)^2大于等于0,所以x^3+y^3大于等于x

已知x+y+z=1,x2+y2+z2=2,x3+y3+z3=3,求xy(x+y)+yz(y+z)+zx(z+x)的值

∵(x+y+z)(x²+y²+z²)=x³+y³+z³+x²(y+z)+y²(x+z)+z²(x+y)∴1*2

已知x+y=1,则代数式x3+3xy+y3的值是______.

x3+3xy+y3=(x+y)(x2-xy+y2)+3xy,=(x2-xy+y2)+3xy,=(x+y)2-3xy+3xy,=1.

求函数f(x,y)=x3-y3+3xy的极值

f'x=3x^2+3y=0-->y=-x^2f'y=-3y^2+3x=0-->y^2=xx=y^2=x^4-->x=0,1,-->y=0,-1f"xx=6x,f"yy=-6y,f"xy=3f(0,0)

⒈-4x^ay+x²y^b=-3x²y,则a+b= ⒉若x+y3,xy=1,则x²+y&#

(1)因为两个式子能合并同类项,∴相同字母的指数相同即a=2,b=1,∴a+b=3(2)x²+y²=(x+y)²-2xy=9-2=7(3)x²+3x+2=x&#

若x3次方+y3次方+1=19,x平方y-xy平方=-30,求代数式(x3次方-+y3次方)+(3xy平方-x平方y)-

要求的式子=(x³-y³)+(3xy²-x²y)-2(x²y-y³)=x³-y³+3xy²-x²y-

题目是求函数f(x,y)=x3次方+y3次方-3xy=0的极值

df/dx=3x^2-3y=0df/dy=3y^2-3x=0得驻点(0,0)(1,1)A=d^2f/dx^2=6xC=d^2f/dy^2=6yB=d^2f/dxdy=-3①对驻点(0,0)A=0B=-

解方程组xy(x+y)=30 x3+y3=35

(x+y)^3=X^3+3X^2Y+3XY^2+Y^3x^2y+xy^2=303x^2y+3xy^2=90x^3+Y^3=35

证明:当x,y为实数,且x+y=1时,x3+y3-xy的值是非负数.

∵x+y=1∴x3+y3-xy=(x+y)(x2+y2-xy)-xy=x2+y2-2xy=(x-y)2≥0即x+y=1时,x3+y3-xy的值是非负数.

求函数f(x,y)=x3+y3-3xy的极值

f'x=3x^2-3yf'y=3y^2-3xf'x=0,f'y=0即x^2-y=0y^2-x=0消去yx^4-x=0即x(x-1)(x^2+x+1)=0x=0或1y=0或1x=y=0时f(x,y)=0

求函数的极值:f(x,y)=x3+8y3-6xy+5

求偏导另其等于0即可

x+xy+y=0 x3+x3y3+y3=12 三是次数、求解方程组

x^3+y^3+x^3y^3=12,x^3+y^3+x^3y^3+1=13,(x^3+1)(y^3+1)=13(x+1)(x^2-x+1)(y+1)(y^2-y+1)=13;x+y+xy=0,x+y+

已知X+Y=1,求X3次方+Y3次方+3XY的值

这是要立方和公式,x^3+y^3+3xy=(x+y)(x^2-xy+y^2)+3xy=x^2-xy+y^2+3xy=(x+y)^2=1

已知方程x3+3xy+y3=0确定y为x的函数 求dy/dx

两边对x求导注意y为x的函数3x^2+3(y+x*dy/dx)+3y^2*dy/dx=0从而dy/dx=-(x^2+y)/(x+y^2)有不明白的留言

推导公式:(x+y)(x2-xy+y2)=x3+y3.

左边=x3-x2y+xy2+x2y-xy2+y3=x3+y3=右边

已知x-y=-1 求 x3+3xy-y3的值 x3,y3就是x的三次和y的三次

x3+3xy-y3=(x-y)(x^2+y^2+xy)+3xy=-x^2-y^2+2xy=-(x-y)^2=-1