x^2y^2 (x^3 y^3)在x,y趋于0,0时的二重极限-搜答案-神马作文网

(x-y)^2-(x-y)^3=(x-y)^2[1-(x-y)]=(x-y)^2(1-x+y)2.（x+y）^2-（x+y）^3=（x+y)^2[1-(x+y)]=(x+y)^2(1-x-y)3、（x

写清楚点点比如说前面是X/X还是X/(X-Y)打上括号分段这样才能清楚的做

(x+y)(x+y)^2(-x-y)^3=－(x+y）^6

3x^2(x-y)+6x(y-x)=3x^2(x-y)-6x(x-y)=(x-y)(3x^2-6x)=3x(x-y)(x-2)

X+Y分之X-Y等于3x=-2yX+Y分之2(x-y)减X+Y分之3X+Y=(-x-3y)/(x+y)=1

因为(x-y)/(x+y)=3,则(x＋y)/(x－y)＝1/3则5(x-y)(x+y)-(x+y)/2(x-y)＝5*3-1/(3*2)=15-1/6=89/6

计算:(-x-2y) * (3x-y)

(-x-2y)*(3x-y)=-3x^2-5xy+2y^2

(x-y)^5*(y-x)^3*(x-y)^2=-(x-y)^5*(x-y)^3*(x-y)^2=-（x-y）^(5+3+2)=-(x-y)^10

(x-3y)(x+y)-(x-2y)(x+2y)-(x-y)平方=x²-2xy-3y²-x²+4y²-x²+2xy-y²=(x²-

=(x-y)[(3x+y)-(2x+3y)]*(x-y)=(x-y)*(x-y)(3x+y-2x-3y)=(x-y)(x-y)(x-2y)到底是化简,还是?=(x*x-2xy+y*y)(x-2y)=x

解题思路：根据题意，由整式的运算的知识整理，分析可以求得解题过程：

解代数式得：-3x的平方y-2y的三次方因为1/2的平方=-1/2的平方,所以结果仍正确给分吧!嘿嘿!

[x(x^2y^2-xy)-y(x^2-x^3y)]/(3x^2y)={x[xy(xy-1)]-y[x²(1-xy)]}/(3x²y)=[x²y(xy-1)-yx&sup

(x+y)^2-3(x+y)=(x+y)(x+y-3)

(2X-3y)-(5x-y)

(2X-3y)-(5x-y)=2x-3y-5x+y=2x-5x-3y+y=(2x-5x)+(-3y+y)=-3x-2y这样写总是全过程了吧

1.（2x+3y)^2-(2x+y)(2x-y)=(2x+y)（2x+3y-2x+y）=4y(2x+y)代入原式=7/3.2..[（x-y)^2+(x-y)(x+y)]/x=[（x-y)(x-y+x+

原式=x²-2xy+y²+6x²+3xy-4xy-6x²+xy=x²-2xy+y²=（x+y）²当x=2分之1,y=1时,原式=（

[3x^2-2x(x+y)+y(2x-y)]÷(x+y)=[3x^2-2x^2-2xy+2xy-y^2]÷(x+y)=(x^2-y^2)÷(x+y)=(x+y)(x-y)÷(x+y)=x-y=1/2-

(x+3y-4)(2x-y)

原式等于2x^2-xy+6xy-3y^2-8x+4y=2x^2+5xy-3y^2-8x+4y

(x+y)^2-(x+y)^3 .

(x+y)^2-(x+y)^3=(1-x-y)(x+y)^2(x-y)^2-(x-y)^3==(1-x+y)(x-y)^2