xy五次方=5-搜答案-神马作文网

4再问：这位我还要过程再答：由题意得：x+1=0,2x-y+4=0解得：x=-1,y=2∴原式=xy(x^4+y^4)=-2(1+16)=-34

(9x²-6xy+y²)+(4x²-4x+1)=0(3x-y)²+(2x-1)²=0所以3x-y=0,2x-1=0x=1/2,y=3x=3/2所以原式

题目应是已知XY的平方=－2,求XY(2X³Y的七次方-5X²Y的五次方-Y)的值已知XY的平方=－2,XY(2X³Y的七次方-5X^2Y的五次方-Y)的值=XY^2(2

(－5xy)²·(-xy)³+(4x²y-3x)(-x³·y^4)+x^5·y^5=25x²y²·（-x³y³）-4x^

原式=√(12xy²)+√(3x^5)-y√(3xy²)=√(4y²)×√(3x)+√x^4×√(3x)-y×√y²×√(3x)=|2y|×√(3x)+x

(3x-5x³)的五次方=?

-3125x^11+7500x^10--5375x^9-1800x^8+3945x^7-1620x^6+243x^5

原式=-x^3y^6+x^2y^4+xy^2=27+9+xy^2

-xy(x³y七次方-3x²y五次方-y)=-xy[(x³y^6)y-3(x²y^4)y-y]=-xy[(xy²)³y-3(xy²

-xy(x^2y^5-xy^3-y)=x^2y^4+xy^2-x^3y^6=(xy^2)^2+xy^2-(xy^2)^3

-xy(x²y的五次方-xy的三次方-y)=-x³y的6次方+x²y的4次方+xy²=-（xy²）³+（xy²）²+xy

x^3+y^5=±235或±5

xy的五次方-81x的五次方y=xy(y⁴－3⁴x⁴)=xy(y²＋9x²)(y²－9x²)=xy(y²＋9x&#

原式=-x^3y^6+x^2y^4+xy^2=-(xy^2)^3+(xy^2)^2+xy^2=-(-2)^3+(-2)^2+(-2)=-(-8)+4-2=10

5x五次方-15x三次方y-20xy平方=5x（x的4次方-3x²y-4y²）=5x(x²-4y)(x²+y)如果本题有什么不明白可以追问,

(-xy)的五次方除以(-xy)的三次方=(-xy)的5-3次方=(-xy)²=x²y²再问：不好意思，是（-xy）的五次方除以（-xy）的二次方再答：=-x³

-(xy)²,把(-1)³先提出来,算完再乘上去

1.000000000000001.000000000000002.0000000000000032.00000000000003.00000000000000243.0000000000004.00

原式=-x³y^6+x²y^4+xy²=-(xy²)³+(xy²)²+(xy²)=-2³+2²+2=

－xy(x²y的五次方－xy³－y）=-x³y^6+x²y^4+xy²=-(xy²)³+(xy²)²+xy&#

13x²-6xy+y²-4x+1=0即(9x^2-6xy+y^2)+(4x^2-4x+1)=0∴(3x-y)^2+(2x-1)^2=0x,y在实数范围内(3x-y)^2(2x-1)