x>0,y>0,x分之1 y分之9=1
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x-3y=0x=3y(2x+y)/(x^2-2xy+y^2)÷1/(x-y)=(2x+y)/(x-y)^2÷1/(x-y)=(2x+y)/(x-y)^2*(x-y)=(2x+y)/(x-y)=(2*3
2x-y+1的绝对值+(3x+2分之3y)平方=0则2x-y+1=03x+3y/2=0,则2x-y=-1①2x+y=0②①+②,得4x=-1,则x=-1/4①-②,得-2y=-1,则y=-1/2x+y
|2分之5x-y|+y²-10y+25=0|2分之5x-y|+(y-5)²=0∴5x/2-y=0y-5=0∴x=2y=51-x-2y分之x-y×x平方-y平方分之x²-4
x²+y²+6x-4y+13=0(x+3)^2+(y-2)^2=0x=-3y=2(y-1/x)/(x-1/y)=(2+1/3)/(-3-1/2)=-2/3
x(y分之1+z分之1)+y(x分之1+z分之1)+z(x分之1+y分之1)=x/y+x/z+y/x+y/z+z/x+z/y=(x+z)/y+(x+y)/z+(y+z)/xx+y+z=0则:x+y=-
(x+y)(x分之1+y分之4)=1+x分之y+y分之4x+4=5+x分之y+y分之4x≥5+2√4=9所以(x+y)(x分之1+y分之4)的最小值是9
②*2-①得,5/y+11=0∴y=-5/11代入②得,1/x-44/5+6=0∴x=5/14经检验,符合题意∴方程组的解是:x=5/14y=-5/11
由4x+y-4x-6y+10=0得(4x-4x+1)+(y-6y+9)=0(2x-1)+(y-3)=0(2x-1)=0(y-3)=0x=1/2y=3代入所求算式即可求出结果(不好意思,看不清你的所求算
令(y+z)/x=(z+x)/y=(x+y)/z=ky+z=kxx+z=kyx+y=kz2(x+y+z)=k(x+y+z)2(x+y+z)=k(x+y+z)(2-k)(x+y+z)=0(x+y+z≠0
用x分之3加y分之4乘以(x+y),然后化简,再用均值不等式就出来了……(3/x+4/y)乘(x+y)等于7+3y/x+4x/y然后由于x,y大于0,所以用均值不等式即可……
X/A+Y/B+D/C=1,A/X+B/Y+C/Z=0,求X/A+Y/B+Z/C的值?(BCX+ACY+ABD)/ABC=1====>BCX+ACY+ABD=ABC==>BCX+ACY=ABC-ABD
用反证法:假设1/x+y=2;因为x>0y>0,所以1+y≥2x1+x≥2y,所以1+y+1+x≥2x+2y即2≥x+y,与条件x+y>2相矛盾即假设不成立故原命题成立
1.令x/2=y/3=z/4=k,则有:x=2ky=3kz=4k所以:(2x+y-z)/(x+y+z)=(2×2k+3k-4k)/(2k+3k+4k)=1/32因为x^2+y^2+2x+4y+4=0即
1、(xy分之x²-y²)×(x-y分之x)-(y分之x);=(x+y)(x-y)/xy×x/(x-y)-x/y=(x+y)/y-x/y=(x+y-x)/y=12、6xy²
再答:不明白的地方可以追问,望采纳,谢谢
y(负数)—y+1-x)————x+1(正数)若y+1-x=0,x=y+1,得0>y>-1,1>x>0若y+1-x>0,y+1>x>0,得0>y>-1,〉x>0若y+1-xy+1>0,得0>y>-1,
5x=-3yx=-3|5y直接带进去得答案,或者=2\3x-2|3x+2|x+y的和乘(x+y)除以x-y|x=2乘x\x-y=2(-3\5y)\(-3\5y-y)=3\4手机果然不行.
原式=5x根号(xy)/3根号(y/x)*1/3根号(x/y)=5/9*根号(xy*x/y*x/y)=5x/9y根号(xy)
y=1+1/x=1+1/(1+y)y-1=1/(1+y)(y-1)(1+y)=1y²-1=1y²=2y=±√2再问:不对,答案没一个符合,这是选择题:A.-1B.1+xC.-xD.
解;(x/y-y/x)=(x²-y²)/xy(y分之x-x分之y)除以(x+y)=(x-y)/xy=0∴x=y