X=7189.23.Y=10027.38转换成渔山独立坐标系

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X=7189.23.Y=10027.38转换成渔山独立坐标系
x+y/4=100

x=50,y=200;x=80,y=80;x=70;y=10;好多呢嘛.

根据x+x+x+y+y=54,x+x+y+y+y=56,求出x.y的值

x+x+x+y+y=54,x+x+y+y+y=56得出3X+2Y=54,2X+3Y=56扩大后得出6X+4Y=108,6X+9Y=118两式相减得出Y=2得出X=50/3

(x+y-z)(x-y+z)=

[x+(z-y)][x-(z-y)]=x-(z-y)记得采纳啊

x、y都是自然数,且x除以y等于100,那么(x、y)=?【x、y】=?

最大公约数(x、y)=y最小公倍数【x、y】=x*y/100

已知X+Y=100,X*Y=100

X+Y=100,X*Y=100设t^2-100t+100=0t=100+√10000-400/2=50+20√6或t==50-20√6所以x/y==(50+20√6)/(50-20√6)=(5+2√6

3x+4y=100 x+y=33 x+Y=33 求x和y的值,

把X+Y=33乘3得3X+3Y=99用3X+4Y=100去减3X+3Y=99得到Y=1把Y=1带入X+Y=33得X=32X=32Y=1

因式分解下列式子:x(x-y)+y(y-x)=?

x(x-y)+y(y-x)=x(x-y)-y(x-y)=(x-y)(x-y)=(x-y)²明教为您解答,请点击[满意答案];如若您有不满意之处,请指出,我一定改正!希望还您一个正确答复!祝您

解方程.100/(X+Y)+64/(X-Y)=9;80/(X+Y)+80/(X-Y)=9

把X+yX-y看成整体X+Y=20X-Y=16X=18Y=2

x+y=5; x^y+y^x=17

X=2,Y=3或X=3,Y=2

求y'=y/(y-x)

∵令y=xt,则y'=xt'+t代入原方程,得xt'+t=t/(t-1)==>xt'=(2t-t^2)/(t-1)==>(t-1)dt/(2t-t^2)=dx/x==>2dx/x+[1/t+1/(t-

已知X-Y/X+Y=3,求代数式2(x-y)/X+Y-3X+Y/X+Y

X+Y分之X-Y等于3x=-2yX+Y分之2(x-y)减X+Y分之3X+Y=(-x-3y)/(x+y)=1

X+Y=7(100X+Y)-(10Y+X)=(10Y+X)-(10X+Y)

(100X+Y)-(10Y+X)=(10Y+X)-(10X+Y)100X+Y-10Y-X=10Y+X-10X-Y99X-9Y=9Y-9X-18Y=-108XY=6X把Y=6X代入X+Y=7得X+6X=

已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)

因为(x-y)/(x+y)=3,则(x+y)/(x-y)=1/3则5(x-y)(x+y)-(x+y)/2(x-y)=5*3-1/(3*2)=15-1/6=89/6

X-Y=500 (X-300)/Y*100%=120%

由X-Y=500得Y=X-500代入(X-300)/Y*100%=120%(X-300)/(X-500)=1.2X-300=1.2(X-500)X-300=1.2X-6000.2X=300所以X=15

[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x其中x=2012 y=2013

先一个一个的展开括号项,再同项合并就行了啊[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x=[xx-xy-(xy-yy)+x(x-y)+y(x-y)]÷2x=[xx-xy-xy+yy+xx-

If two even number x,y satisfy equation x×x+100=y×y,x

X=24Y=26XY=624再问:翻译再答:哦……若有两个偶数,满足……,则……可以吗?

x+y=100,85%x+75%y=81

x+y=100所以0.75x+0.75y=100*0.75=75(1)85%x+75%y=810.85x+0.75y=81(2)(2)-(1)0.1x=6x=60y=100-x=40

二元函数f(x,y)=x+y/x-y,求f(y/x,x/y)

假设:X=Y/XY=X/Y带入函数就是:F(y/x,x/y)=(y/x+x/y)/(y/x—x/y)=x²+y²)/(y²-x²)希望可以帮助你!

【(2x+y)²-y(y+4x)-8x】÷2x,其中x=100

 再答:如有疑问,请赐教,

) y=cos(x-y)

1.两边求导得:y'=-sin(x-y)(1-y')解得y'=sin(x-y)/[sin(x-y)-1]2.y'=-e^-xy''=e^-xy'"=-e^-x3.y'"=(e^2x)'"(sinx)+