x-8y因式分解-搜答案-神马作文网

xy+x+y+1因式分解

(x+1)(y+1)

原式=2y(x²-4x+4)=2y(x-2)²

8（x平方-2y平方)-x(7x+y)+xy=8x平方-16y平方-7x平方-xy+xy=x平方-4y平方=(x-2y)(x+2y)手机提问的朋友在客户端右上角评价点【满意】即可.再问：太棒了！连我这

x(x-y)+4(y-x)=x(x-y)-4(x-y)=(x-y)(x-4)=(x-y)(X+2)(X-2)

因式分解x2+y-xy-x

x²＋y－xy－x＝﹙x²－xy﹚＋﹙y－x﹚＝x﹙x－y﹚－﹙x－y﹚＝﹙x－y﹚﹙x－1﹚

(x-y)^2-8(x-y-2)=(x-y)^2-8(x-y)+16=[(x-y)-4]^2=(x-y-4)^2

½x²y四次方-8x²=1/2x²(y的4次方-16)=1/2x²(y²+4)(y²-4)==1/2x²(y²

解3x²y+6xy-4x-8=(3x²y-4x)+(6xy-8)=x(3xy-4)+2(3xy-4)=(x+2)(3xy-4)

1-x-y+xy 因式分解

1-x-y+xy=(1-x)-(y-xy)=(1-x)-y(1-x)=(1-x)(1-y)

=(x-y)^2-2*4(x-y)+4^2=(x-y-4)^2

（x-2y)²-4x+8y+4=(x-2y)²-4(x-2y)+4=(x-2y-2)²

因式分解xy-x-y+1

xy-x-y+1=x(y-1)-y+1=x(y-1)-(y-1)=(y-1)(x-1)

因式分解：x^4-y^4

x^4-y^4=(x²-y²)(x²+y²)=(x-y)(x+y)(x²+y²)

原式=3x(x-2y)-4(x-2y)=(x-2y)(3x-4)

(x-2y)²+4x-8y+4=(x-2y)²+4(x-2y)+4=[(x-2y)+2]²a³-a²-a+1=a²(a-1)-(a-1)=(

xy-x-y+1因式分解

(x-1)(y-1)

2x^4y^4-x^8-y^8=-(x^8-2x^4y^4+y^8)=-(x^4-y^4)^2=-(x^2+y^2)^2(x+y)^2(x-y)^2

您好：x方(x-y)+(y-x)=x方(x-y)-(x-y)=(x²-1)(x-y)=（x+1）（x-1）（x-y）如果本题有什么不明白可以追问,如果满意记得采纳如果有其他问题请采纳本题后另

原式=x²(x-y)-(x-y)=(x²-1)(x-y)=(x+1)(x-1)(x-y)

(x+y)的平方+2*4(x+y)+4的平方(x+y)=(x+y+4)的平方