x+y+z=63 600x+300y=z乘500z怎么解?
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[x+(z-y)][x-(z-y)]=x-(z-y)记得采纳啊
∑是循环和例如∑a=a+b+c∑a^2=a^2+b^2+c^2∑(z-y)(x-y)/(x+y-2z)(y+z-2x)=∑(z-y)(x-y)(x+z-2y)/(x+y-2z)(y+z-2x)(x+z
(1)原式=x+y+z)(-x+y+z)(x-y+z)(x+y-z)=[(x+y+z)(x+y-z)]*{[z+(x-y)][z-(x-y)]}=[(x+y)^2-z^2][z^2-(x-y)^2]=
(x+y-z)(x-y+z)-(y+z-x)(z-x-y)=(x+y-z)(x-y+z)+(y+z-x)(x+y-z)所以公因式是(x+y-z)
方程(1)+(2)得:3x-z=9④,方程(2)+(3)得:2x-z=7⑤,④-⑤得:x=2,把它代入⑤得:z=-3,把它代入(1)得:y=-3,∴原方程的解为x=2y=−3z=−3.
∵x-2y+z=(x-y)-(y-z),x+y-2z=(y-z)-(z-x),y+z-2x=(z-x)-(x-y).设x-y=a,y-z=b,z-x=c,则原式=-ac/(a-b)(b-c)+(-ba
正整数?取对数即证:2xlnx+2ylny+2zlnz>(y+z)lnx+(x+z)lny+(x+y)lnzx>y>z,lnx>lny>lnz由排序不等式得xlnx+ylny+zlnz>ylnx+zl
z/(x-y)×y/(x+y)=zy/(x-y)(x+y)=zy/(x²-y²)再问:还有两道题!麻烦你了!1.已知x-1/x=2,求x²/x四次方-x²+12
X--水平横向方向;Y--水平竖向方向;Z--垂直竖向方向.
(x+y+z)^5-(x+y-z)^5-(x+z-y)^5-(z+y-x)^5=80xyz(x^2+y^2+z^2)注:x^5,y^5,z^5之类的是被消掉了.我的结果100%是正确的,你再算算吧.朝
2x+y+3z=38①3x+2y+4z=56②4x+y+5z=66③③-①得:2x+2z=28,即x+z=14④,①×2-②得:x+2z=20⑤,由④和⑤组成方程组:x+z=14x+2z=20,解得:
X+Y+Z
25xy^2z^2(x+y-z)-30xyz(z-x-y)^2+5xyz^3(z-x-y)=25xy^2z^2(x+y-z)+30xyz(x+y-z)^2-5xyz^3(x+y-z)=5xyz(x+y
3元一次方程,好像是初一的问题哦.根据前面两个等式可以得出x=3zy=z(平方)/32x+3y+4z=2*(3z)+3*(z方/3)+4z现在变成了一元二次方程,你应该会解吧.
f=x+1f+u=2x+3f+u+c=3x+8f+u+c+k=4x+15f(f,u,c,k)=(x+1)(2x+3)(3x+8)(4x+15)
应用平方差公式a^2-b^2=(a+b)(a-b)(x+y+z)(x+y-z)(x-y+z)(-x+y+z)=[(x+y)^2-z^2][z^2-(x-y)^2]=-z^4+[(x+y)^2+(x-y
(x+y+z)(-x+y+z)(x-y+z)(x+y-z)=-[(x+y+z)(x+y-z)][(x-y+z)(x-y-z)]=-[(x+y)²-z²]*[(x-y)²-