vb编程s=1-13 15-17 19求和代码
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数学计算可以简化过程:因为1-2=-1,3-4=-1...所以得出-1+(-1)+...,重复(100/2)次,即代码为(这是最简单而且最快速的办法):DimsAsInteger=-(100/2)如果
dims,a,is=1a=1i=0DoWhilea
PrivateSubForm_Activate()a5EndSubSuba(nAsLong)DimiAsLongFori=1TonSum=Sum+1/f(i)NextiPrintSumEndSubFu
无语第二个len(Text2.Text)=Len(Text2.Text)-1能赋值么?再问:那怎么改让Text1删一个字符text2也删一个再答:用函数(函数自己找,不多说)去掉他们值的最后一个字符,
for循环修改下fori=1to2n-1step2a=a+inexti
PublicFunctions(n)Dimi,j,t,resFori=1Tont=1Forj=1Toit=t*jNextres=res+tNexts=resEndFunction
你好!PrivateSubForm_Click()DimiAsIntegerDimsAsIntegerFori=1To100s=s+iNextiPrintsEndSu
PrivateSubCommand1_Click()DimiAsLong,Si=0:S=0WhileSi=i+1S=S+i*(i+1)WendText1.Text=SText2.Text=iEndSu
Private Sub Command1_Click()Dim F(11), i As LongF(0) = 
……t=1s=0Fori=1To10t=t*is=s+tNexti再问:这个要用什么下拉列表呢?再答:Textbox代码是在Botton中完成!
OptionBase1'因为用了这句,所以数组下标从1开始PrivateSubcommand1_click()Dimdd=Array(1,2,3,4,5)n=1Fork=5To3Step-1s=s+d
PrivateSubCommand1_Click()DimiAsInteger,jAsInteger,nAsIntegerDimsum1AsLong,sum2AsLongn=inputbox("请输入
PrivateSubCommand1_Click()DimnAsLongDimiAsLongDimsumAsDoublen=Val(Text1.Text)sum=1#Fori=2Ton'sum=sum
mid从指定位置截取指定长度的容.mid(string,start,len)
PrivateSubCommand1_Click()dimiasintegerfori=1to55step2m=m+inextiprintmendsu
代码如下:n=inputbox("输入n的值")s=0a=1b=1fori=1tons=s+a/bb=a+ba=b-anextiprints
Dimi,sAsIntegerFori=2To100step2s=s+iNexti
用Sub过程实现:PrivateSubCommand1_Click()DimtAsLongs=0fac01,ts=s+tfac02,ts=s+tfac03,ts=s+tPrint"s=1!+2!+3!
DimNAsLongDimiAsLongN=Val(InputBox("请输入数字","输入数字"))Fori=1ToNs=s+i^2NextMsgBoxs再问:请输入数字填写什么啊。。小白不懂求大神
PrivateSubCommand1_Click()DimnAsInteger,iAsIntegerDimxAsVariant,sumAsDoublen=20x=CDec(x)x=1Fori=1Ton