sin²3x导数
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[sin(x^5)]'=cos(x^5)×(x^5)'=cos(x^5)×5x^4=5x^4cos(x^5)
y=sin³xy'=(3sin²x)×(sinx)'y'=3cosxsin²x
12cos(3x)cos(x)-4sin(3x)sin(x)
(sinx)^2求导是2sinxcosxsin(x^2)求导是2xcos(x^2)
∫sin²xdx=∫(1-cos2x)/2dx=1/2·∫1dx-1/2·∫cos2xdx=x/2-1/4·sin2x+C所以x/2-1/4·sin2x+C的导数是sin²x
f'(x)=lim(Δx-->0)Δy/Δx=lim(Δx-->0)[sin(3x+3Δx+1)-sin(3x+1)]/Δx=lim(Δx-->0)[2cos(3x+3/2*Δx+1)sin(3Δx/
5sin^4x*cosx
y'=sin‘(3x+5)×(3x)'=3cos(3x+5)
y=sin^3x是复合函数可以设t=sinxt'=cosxy=t^3y'=3t^2*t'y'=3sin^2x*cosx
y=sin^3x+sinx^3y'=3sin²xcosx+cosx³*3x²=3sin²xcosx+3x²cosx³
∵y=x^(sinx)∴lny=sinx*lnx两边求导:y'/y=cosx*lnx+(sinx)/x∴y'=y[cosx*lnx+(sinx)/x]=x^(sinx)[cosx*lnx+(sinx)
y=sin³x-sin3x→y'=3sinx·(sinx)'-cos3x·(3x)'→y'=3sin²xcosx-3cosx→y'=3(1-cos²x)cosx-3cos
(sin(x/2))'=(1/2)cos(x/2).再问:帮我做下这个好吗?
y‘=[sin²(cos3x)]'=2sin(cos3x)×[sin(cos(3x))]'=2sin(cos3x)cos(cos(3x))(cos3x)'=sin[2(cos3x)]×(-s
用链式法则:y=sin(πx)dy/dx=dsin(πx)/d(πx)*d(πx)/dx=cos(πx)*π(dx/dx)=cos(πx)*π=πcos(πx)
y'=[2x(x+3)-x²]/(x+3)²=(x²+6x)/(x+3)²y'=cos(2x²+x)·(2x²+x)'=(4x+1)cos(
通过复合函数求导,可以得到y'=cos(3x-π/6)*3=3cos(3x-π/6)欢迎追问~
(x*sinx*cosx)'=(1/2xsin2x)'=1/2(sin2x+xcos2x*2)=1/2sin2x+xcos2x
设sinx=t 所以sinx³+sin³(3x)=t³ sin3x=sin(x+2x)=3sinx-4sin³x=3t-4t³ sinx