随机生成100个0-10的整数,输出这100个数的平均数.

分两步呗.第一步：生成随机数第二步：排序这里只说第一步的内容,第二步,我想你的算法书中都有说吧.先说生成一个0-1之间的随机数很容易吧?doublek=Math.Random();而获得一个0-100

dima(10)asintegerdimiasinteger,kasinteger,pasintegerdimmasintegerdimnasintegerfori=1to10a(i)=int(rnd

PrivateSubForm_Load()Dima(10),i,x,jAsIntegerDimyAsStringFori=0To9Randomizea(i)=Int(Rnd(1)*101)x=x+a(

importjava.io.BufferedWriter;importjava.io.File;importjava.io.FileWriter;importjava.io.IOException;p

以下是我现写的importjava.util.Random;publicclassWord{\x09publicstaticvoidmain(Stringargs[]){\x09\x09intmax=

Dimk%Dima%(1To10)PrivateSubCommand1_Click()Fori=1To10Randomizea(i)=Int(Rnd*100+1)NextPrint"a数组:"k=1F

PrivateSubCommand1_Click()DimiAsInteger,myTempNumAsInteger,myTempStrAsStringRandomize(Timer)Fori=1To

PrivateSubCommand1_Click()Dima(1To2,1To5)AsInteger,i,j,k,fAsBooleanRandomizeFori=1To2Forj=1To5a(i,j)

生成按钮代码：PrivateSubCommand1_Click()RandomizeFori=1To100t=Int(Rnd()*900+100)IftMod2=0ThenList1.AddItemt

Randomize初始化随机数发生器Rnd()获取0~1之间的随机数,乘以90后再加上10,取整后就是10~90之间的了然后挑选出来Mod3=0的数据排序就是了再问：就是mod3=0后不会排序啊再答：

'声明变量dimMin_numasintdimMax_numasintdimSum_numasintdimArr_num(9)asint'赋予初始值Min_num=101Max_num=-1Sum_n

#include#include#include#defineMAX100voidqicksort(int*a,int,int);voidchoosesort(int*a,int,int);voidi

PrivateSubForm_Load()RandomizeDimintRndAsIntegerDimstrRndAsStringDimstrOushuAsStringDimiAsIntegerFor

#include#include#includeintmain(){inti,a[10],m,t=0,s=0;floatn;srand((unsigned)time(NULL));for(i=0;i

#include#include#includeintmain(){inti,a[10],m,t=0,s=0;floatn;srand((unsigned)time(NULL));for(i=0;i

importjava.io.File;importjava.io.FileNotFoundException;importjava.io.FileWriter;importjava.io.IOExce

至于你的程序的问题,在你的最外层循环for(j=0;j

直接写main函数了publicstaticvoidmain(String[]args){int[]forSort=newint[100];for(inti=0;iforSort[i]=(int)(j

importjava.util.Random;importjava.io.*;publicclassTest{publicstaticvoidmain(String[]args)throwsIOExc

题目的含义混淆啊保证相同整数的个数为偶数,这就不叫随机了而且随机生成正数,是不会出现整数的,在这种情况下相同整数的个数总为0,满不满足条件?