通过调用函数计算任意三个整数的和

main(){ints;s=getfactorial(6)+getfactorial(10)+getfactorial(20)printf("s=%d",s);}intgetfactorial(int

#includeintfun(intn){ints=0;while(n){s+=n%10;n=n/10;}returns;}main(){intn;scanf("%d",&n);printf("%d\

#includeintswap(intn){inti,s=1;for(i=2;i

#include<stdio.h>int getmax(int a,int b){      re

#include"stido.h"#definePi3.1415926floatArea(flaotr){returnPi*r*r;}voidmain(){inti;floats=0,r;for(i=

先定义数组ainti=0;intj=0;doublepa=0;for(i=0;i再问：能不能来个完整版的，我一窍不通，谢谢了，再答：c语言或者c++么？再问：是的，c++再答：先采纳吧，十五分钟给你，

楼主你好,这是源程序,是用辗转相除法写的#includeintmax(intp_a,intp_b){\x09if(p_b==0)\x09\x09returnp_a;\x09else\x09\x09re

voidmain(){inti,n;scanf("%d",&n);for(i=0;i*i

VC++编程#includeusingnamespacestd;intmax(intx,inty);//子函数的声明,子函数的参数的类型intmain(){intMAX,x,y;cin>>x>>y;M

voidfun(inta,intb,intc,int*sum,int*mul){*sum=(a+b+c);*mul=(a*b*c);}

#includevoidmyChange(int&a,int&b,int&c);voidmain(){\x05inta=2,b=3,c=1;\x05myChange(a,b,c);\x05cout

#include"stdio.h"longintcal(longinta){for(longinti=1,sum=1;i

源码如下：#includeintsum(inta,intb){\x09returna+b;\x09}intmain(){\x09intm=1,n=2,k=3;\x09intt=sum(sum(m,n)

#include"stdio.h"#include"math.h"doubleGetP(int*p,intm,intn){intmax=*p;intmin=*p;inti,j;doublepp;for

a=0'和的变量fori=0to100ifimod70thena=a+i'如果不能被7整除,就是除7的余数不等于0的话,累加起来nextimsgboxa再问：是要这样的窗体。。再答：学程序的人没有人会

intsum(intn){if(0>n){n=-n;}intsum=0;while(0!=n){sum+=n%10;n/=10;}returnsum;}

#include#include#defineA12#defineB9voidpaixu(intm[],intshu);main(){inta[A];intb[B];inti;doublea1,b1;

voids(folata,folatb,folatc){folatp;p=(a+b+c)/2;S=√[p(p-a)(p-b)(p-c)];returns;}

java版实现public class Calculator{    public int calTest(int&nb

#includeintGcd(intM,intN){intRem;while(N>0){Rem=M%N;M=N;N=Rem;}returnM;}voidmain(){inta,b