输入一维数组的6个元素,将最小值与第一个数交换,最大值与最后一个交换

OptionExplicitDimarr(100)AsIntegerDimarr1(100)AsIntegerDimiAsIntegerPrivateSubCommand1_Click()Fori=1

你没有把xiao和da初始化!你先把xiao=0；da=0；（数组第一个数）你再试一下!你如果不初始化的话,在if条件中有些情况会出现xiao或da未赋值,而造成数组越界!一般在运行至出错的,很多是内

#includemain(){intw[8],i,j=0,k=0;for(i=0;i

main(){inti,t,max=0,min=0,w[10];for(i=0;iw[max])max=i;if(w[i]

PrivateSubCommand1_Click()DimA(10)AsLong,IAsLongForI=1To10A(I)=InputBox("请输入第"&I&"个数据","提示","")Print

你好,完成以上功能的代码如下根据你要求的malloc我觉得应该是用C语言来做吧!如果我理解错了,请指正!#include<stdio.h>#include<stdlib.h>i

这道题我也错过好几次...先找最大值,然后更改,再找最小值,再改就可以了...数据范围不大,可以的再问：是的

/>privatesubcommand1_click()dima(1to10)asdoubledimminasdoublefori=1to10a(i)=val(inputbox("请输入数组元素值："

#includeintmain(){intarray[10]={0};inti,min;printf("请输入10个数字：\n");scanf("%d",&array[0]);min=arr

第1题：PrivateSubCommand1_Click()Dimv(1To20)AsDoubleDimvMaxAsDoubleDimvMinAsDoubleDimiAsLongFori=1To20v

试下这个,只需改动  b(i)=a(i\10+1,imod10)换成b(i)=a((i-1)\10+1,(i-1)Mod10+1)如下：PrivateSubform_click()

#include<iostream>#include<iomanip>#include<ctime>using namespace std;in

#includeusingnamespacestd;voidmain(){chara[10];inti,temp;for(i=0;i>a[i];cout

importjava.util.Scanner;publicclassInputTest{publicstaticvoidmain(String[]args){Scannerin=newScanner

#includevoidinput(inta[],intn)//输入{inti;printf("请输入%d个数,用空格隔开\n",n);for(i=0;i

PrivateSubCommand1_Click()Dima()AsIntegern=Val(InputBox("N="))ReDima(n)Print"Before:&

#include#include#defineN20voidmain(){inti,k,j,a[N];k=0;printf("Pleaseinputtwentynozeronumbers\n");fo

题目不完整啊

#includeintmain(){doubled[10],sum=0,ave=0;inti;for(i=0;i

#includevoidmain(){intn,min,a[100],i,t,e;while(scanf("%d",&n)!=EOF&&n